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2 years ago

In the figure below, Find AB Help

Mathematics

1 answer:

Tema [17]2 years ago

4 0

we have:

CD ÷ CA = DE ÷ AB

=> 6 ÷ 11 = 12 ÷ AB

=> AB = 12 × 6 ÷ 11 = 72/11 ≈ 6,5

Answer: 72/11 ≈ 6,5

P/s: CA = CD + AD = 6 + 5 = 11

Ok done. Thank to me :>

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A spinner is divided into eight equal-sized sections, numbered 1 to 8, inclusive. What is true about spinning the spinner one at

zvonat [6]

Answer with explanation:

The number of section into which Spinner is divided =Number from 1 to 8={1,2,3,4,5,6,7,8}

Now, Spinner is Spun once .

The Correct statement among the given statements are:

→1. S={1,2,3,4,5,6,7,8}

→2. If A is a subset of S, A could be {1,2,3} , because , {1,2,3}⊂{1,2,3,4,5,6,7,8}.

→5.If a subset A represents the complement of spinning an odd number, it’s sample space is A={2,,4,6,8}

A=odd number={1,3,5,7}

A's Complement=Even Number={2,4,6,8}

Why, not 3 and 4, because, The number of elements in the set is from 1 to 8, but the subset has three elements, 7,8, and 9.Element, 7 ∈ S, 8∈S, but , 9∈S.

Also, number less than 4, is equal to ={1,2,3}, but in the statement, it is given that,number less than 4, it’s sample space is A={1,2,3,4},which is Incorrect.

7 0

3 years ago

Read 2 more answers

Which of the following is an even function?

nika2105 [10]

Answer:

An even function is:

f(x) = 7

Step-by-step explanation:

An even function accomplish the following condition:

f(x)=f(-x) (1)

Applying (1), we have:

f(x)= (x-1)^2 $\neq$ f(-x) $\neq$ (-x-1)^2
f(x)= 8x $\neq$ f(-x) $\neq$ -8x
f(x)= x^2 -x $\neq$ f(-x) $\neq$ (-x)^2 +x

f(x)=7 = f(-x)= 7

The last one is even.

3 0

3 years ago

In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T

dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + $\frac{h^{2} }{2!}$ f''(a) = 0

$h = \frac{-f'(a) }{f''(a)}$ ± $\frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}$

So, we get the succeeding equation for Newton's method as

$x_{i+1} = x_{i} + \frac{1}{f''x_{i}} [-f'(x_{i})$ ± $\sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]$

Part B.

It is evident that Newton's method fails in two cases, as:

1. if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)

Part C.

In case $x_{i+1}$ is close to $x_{i}$ , the choice that shouldbe made instead of ± in part A is:

f'(x) = $\sqrt{f'(x)^{2} - 2f(x)f''(x)}$ ⇔ $x_{i+1} = x_{i}$

Part D.

As given $x_{i+1}$ = $x_{i}$ = h

or h = $x_{i+1}$ - $x_{i}$

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also, ( $x_{i+1}$ - $x_{i}$ )² = -( $x_{i+1}$ - $x_{i}$ )(f( $x_{i}$ )/f'( $x_{i}$ ))

So, f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also, $x_{i+1}$ = $x_{i}$ -f( $x_{i}$ )/f'( $x_{i}$ ) + [( $x_{i+1}$ - $x_{i}$ )f''( $x_{i}$ )f( $x_{i}$ )]/[2(f'( $x_{i}$ ))²]

6 0

3 years ago

Parallel lines s and t are cut by a transversal r.

AURORKA [14]

Answer:

the answer is <3 and 5

because they add up to 180

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3 years ago

Which set of ordered pairs below is a function?

slega [8]

I dont really feel like graphing it out but i can explain it. so lets say that you had some graph points and when you drew them together it was the shape of a circle so make a line down that circle and the rule is if that circle passes through that line you drew more than 2 times it is not a function, and if it only passes through that line once then it is a function.

6 0

3 years ago