Answer:
![Scale = 1\ in : 8\ ft](https://tex.z-dn.net/?f=Scale%20%3D%201%5C%20in%20%3A%208%5C%20ft)
Step-by-step explanation:
Given
![Scale\ Measurement = 20.5in](https://tex.z-dn.net/?f=Scale%5C%20Measurement%20%3D%2020.5in)
![Actual\ Measurement = 164ft](https://tex.z-dn.net/?f=Actual%5C%20Measurement%20%3D%20164ft)
Required
Determine the scale
The scale is calculated using the following ratio:
![Scale = Scale\ Measurement : Actual\ Measurement;](https://tex.z-dn.net/?f=Scale%20%3D%20Scale%5C%20Measurement%20%3A%20Actual%5C%20Measurement%3B)
Substitute values for Scale and Actual Measurements
![Scale = 20.5\ in : 164\ ft](https://tex.z-dn.net/?f=Scale%20%3D%2020.5%5C%20in%20%3A%20164%5C%20ft)
Divide ratio by 20.5
![Scale = 20.5/20.5\ in : 164/20.5\ ft](https://tex.z-dn.net/?f=Scale%20%3D%2020.5%2F20.5%5C%20in%20%3A%20164%2F20.5%5C%20ft)
![Scale = 1\ in : 8\ ft](https://tex.z-dn.net/?f=Scale%20%3D%201%5C%20in%20%3A%208%5C%20ft)
This implies that: <em>1 inch on scale represents 8 ft in actual measurement</em>
Answer:
similar shape!!!!
Step-by-step explanation:
D is the answer for ur question
Answer:
b
Step-by-step explanation:
Answer:
The above function will get the minimum value at the value of p =14 ....
Step-by-step explanation:
Take the derivative of the given function with p and equate to zero to minimize the given function.
c(p) = p^2 - 28p + 250
(d/dp) c(p) = (d/dp)p^2 - 28p + 250 = 2p-28
(d/dp) c(p) = 0
2p-28 = 0
Move the constant to the R.H.S
2p = 28
Divide both sides by 2
2p/2 = 28/2
p = 14
The above function will get the minimum value at the value of p =14 ....