All categories

3 years ago

A bucket of water is 1/2 full but it still has 3 4/6 gallons of water in it how much water do you need to fill the bucket

Mathematics

1 answer:

xeze [42]3 years ago

6 0

Answer:

7 1/3 gallons

Step-by-step explanation:

If the bucket is half full and still has half to go, you double the current contents of the bucket. 3 4/6 times 2 is equal to 7 2/6 gallons which simplifies to 7 1/3 gallons.

I don't fully understand your question though, if the question is asking how much MORE water is needed to fill the bucket, it's 3 2/3 gallons. If it's asking how much water in TOTAL it would take to fill the bucket completely, it's 7 1/3 gallons.

You might be interested in

Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a

Svet_ta [14]

Answer:

The area that was not painted is $(2x^{2}-6x+6)\ units^{2}$

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

$A=LW$

In this problem we have

$L=2x-3$

$W=x$

substitute

$A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}$

step 2

Find the area that was painted

$A=(3)(x-2)\\A=(3x-6)\ units^{2}$

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

$A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}$

8 0

3 years ago

the perimeter of a rectangle is 50 inches. The length of the rectangle is 10 inches. What method can be used to find the width o

Vinil7 [7]

Answer:

P= 2(l+w)

50=2(10+w)

50=20+2w

50-20=2w

30=2w

w=15

5 0

3 years ago

What is the focus of the parabola? <img src="https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B1%7D%7B4%7D%20x%5E%7B2%7D%20-x%2B3" id="Te

OlgaM077 [116]

We know that
the equation of the parabola is of the form
y=ax²+bx+c
in this problem
y=1/4x²−x+3
where
a=1/4
b=-1
c=3
the coordinates of the focus are
(-b/2a,(1-D)/4a)
where D is the discriminant b²-4ac
D=(-1)²-4*(1/4)*3-----> D=1-3---> D=-2
therefore
x coordinate of the focus
-b/2a----> 1/[2*(-1/4)]----> 2

y coordinate of the focus
(1-D)/4a------> (1+2)/(4/4)---> 3

the coordinates of the focus are (2,3)

3 0

3 years ago

Read 2 more answers

F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?

zhuklara [117]

Answer:

f(-2) = 0

Step-by-step explanation:

Given that:

f(x) = bx^2 + 32

f(2) = b(2)^2 + 32

f(2) = 4b + 32

f(2) = 4b = -32

f(2) = b = -32/4

f(2) = b = -8

Thus;

f(-2) = -8(-2)^2 + 32

f(-2) = -8(4) + 32

f(-2) = -32 + 32

f(-2) = 0

6 0

3 years ago

Read 2 more answers

Consider the cubic function f(x) = x^3 + ax^2 + bx + 4 where (a) and (b) are constants. When f(x) is divided by x-3, the remaind

Debora [2.8K]

Answer:

see explanation

Step-by-step explanation:

Using the Remainder theorem

If f(x) is divided by (x - h) then f(h) = remainder, thus

f(3) = 3³ + a(3)² + b(3) + 4 = 10, that is

27 + 9a + 3b + 4 = 10

9a + 3b + 31 = 10 ( subtract 31 from both sides )

9a + 3b = - 21 → (1)

f(- 1) = (- 1)³ + a(- 1)² + b(- 1) + 4 = 6, that is

- 1 + a - b + 4 = 6

a - b + 3 = 6 ( subtract 3 from both sides )

a - b = 3 → (2)

Rearrange (2) expressing a in terms of b

a = 3 + b → (3)

Substitute a = 3 + b into (1)

9(3 + b) + 3b = - 21 ← distribute and simplify left side

27 + 9b + 3b = - 21

12b + 27 = - 21 ( subtract 27 from both sides )

12b = - 48 ( divide both sides by 12 )

b = - 4

Substitute b = - 4 into (3)

a = 3 - 4 = - 1

Hence a = - 1 and b = - 4

8 0

3 years ago