Answer:
C = 3 √ 5
(since 9 is a perfect square), we can simplify radical 45 to 3 times radical 5
B √ 9*5 is true but not simplified.
We need to find a square numbers that divide into 45
We find 9
And show a * b = c
c= 45
so a * b = 9 * 5 = 3√ 5 is how we arrange this to simplify.
Step-by-step explanation:
The list is
1, 4, 9, 16, 25, 36, 49, 64, 81, 100
We see there are 10 perfect squares 1-100
5 are 1-25
then think 6 , 7, 6 , 9 ,10 squared/ if you cant list them too quickly.
Answers: Using the process of completing the square:
1. Isolate the constant by <u>adding 7 to</u> both sides of the equation:
x^2-6x-7+7=0+7
x^2-6x=7
2. Add <u>9</u> to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced:
x^2-6x+9=7+9
x^2-6x+9=16
3. Write the trinomial x2 – 6x + 9 as squared:
<u>(x-3)^2</u> = 16
4. Use the square root property of equality to get x – 3 = ±<u>4</u> .
sqrt[ (x-3)^2 ] = ± sqrt(16)
x-3 = ±4
5. Isolate the variable to get solutions of –1 and 7.
x-3 = ±4
x-3+3 = ±4+3
x = ±4+3
x1=-4+3→x1=-1
x2=+4+3→x2=7
Answer:
Where’s the table, I’ll help you if you post it so I can see
Step-by-step explanation:
