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insens350 [35]
3 years ago
11

Hello, can you explain this topic im in 6th grade ​

Mathematics
2 answers:
Andrew [12]3 years ago
5 0

Hello there I hope you are having a great day :)

<u>The Topic Shifting digits:</u>

Shifting digits - Putting a digit in a different place. For a example Take the number 358 you would exchange the number from the hundreds that would equal 838 this meaning that you what to make a bigger number than a small one.

Examples:

1. 358 equal 838

2. 204 equal 402

3. 188 equal 881

You are just making them smaller to a greater number :)

Hopefully that helps you :)

 

<u></u>

alexandr402 [8]3 years ago
5 0

Step-by-step explanation:

this is to make you aware what "power" or "value" is associated with what position in a number.

when I write a number like in the example above

795

then the strongest, most powerful value in the whole number is with the digit in the outmost left position.

the second most powerful with the digit in the next position to the right. and sin on.

and the digit in the outmost right position has the least value.

to make sure that there is no overlap between the positions, every position corresponds to a certain power of 10 level. each position to the left is one level higher, and another level higher and so on.

as we start with 10⁰, the levels go up to number of positions - 1.

3 positions means we go up to 10².

795 = 7×10² + 9×10¹ + 5×10⁰

or

42186 = 4×10⁴ + 2×10³ + 1×10² + 8×10¹ + 6×10⁰

by the way, you know that x⁰ = 1 for any value of x.

if we go into the decimals, then the same principle applies also on the right side of the decimal point. each position further right decreases the exponent of 10 by 1.

23.073 = 2×10¹ + 3×10⁰ + 0×10^-1 + 7×10^-2 + 3×10^-3

it is very important when handling and calculating numbers to stay always very aware of the positions the digits have in the actual number(s). and to combine always only the digits in the right corresponding positions for calculations or comparisons.

bottom line of this exercise above is therefore, if you put a smaller digit into the first position (outmost left), then the number value gets smaller, no matter what you do with the remaining digits in their positions.

and the other way around (bigger digit in the first position makes the number value bigger). it gets smaller or bigger with the associated power of 10.

you can imagine these associated powers of 10 as proponents or "bullies" of the corresponding digits. the bigger the exponent of 10, the stronger and effective the "bully".

on the other end :

even if you put a 9 instead of a 0 into the last (outmost right) position, the number value gets a little bit bigger. it has only the weakest "bully" to "make it heard". it only makes a difference, if the other digits are the same.

e.g.

52760 is smaller than 52769.

but

52770 is bigger than 5276x, no matter what digit you put in for x.

this is what this exercise tries to show you, and the playing around with the numbers should create a "feeling" in you to always think about it, even if it is only sub-consciously.

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Your new expression is 6(x^2 + 7x -3).
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There are 48 students in the 6th-grade band. If this represents 30% of the students in 6th grade, how many students are in the 6
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2 years ago
Read 2 more answers
Daeja and Juana solved this equation 6 = 1/2s.
xz_007 [3.2K]

Answer:

Daeja is correct.

Step-by-step explanation:

Equation: 6 = 1/2s

Solve:

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3 years ago
The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,
strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=400 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=80 represent the population standard deviation

n=15 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

400-2.58\frac{80}{\sqrt{15}}=346.708    

400+2.58\frac{80}{\sqrt{15}}=453.292

So on this case the 99% confidence interval would be given by (346.708;453.292)    

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that t_{\alpha/2}=2.98

Now we have everything in order to replace into formula (1):

400-2.98\frac{80}{\sqrt{15}}=338.445    

400+2.98\frac{80}{\sqrt{15}}=461.555

So on this case the 99% confidence interval would be given by (338.445;461.555)    

4 0
3 years ago
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