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gregori [183]
4 years ago
8

How many times does 4 go into 36

Mathematics
2 answers:
attashe74 [19]4 years ago
6 0
In other words they are asking what is 36/4=9
sladkih [1.3K]4 years ago
4 0
4 goes into 36 
9 times

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Plz help me with this . its says determine if it's linear or not linear .explain ur decisison.​
sergey [27]

Answer:

I say that d) is linear because I found the common difference of +2 in the y which makes the line of a graph straight.

And c) is non linear because there is no sequence so if you create a line out of this table, the line of a graph will not be straight.

7 0
3 years ago
Solve for the rate in the eqution d=rt
Zolol [24]

Answer:

<em>The rate of the equation is r when r is a constant</em>

Step-by-step explanation:

     We need to solve for the rate of the equation  

     d = rt

     Differentiating on both sides with respect to time

     \frac{\mathrm{d} d}{\mathrm{d} t} = \frac{\mathrm{d} rt}{\mathrm{d} t}

      Considering r as a constant

       \frac{\mathrm{d} d}{\mathrm{d} t} =  r×\frac{\mathrm{d} t}{\mathrm{d} t}

      where, \frac{\mathrm{d} t}{\mathrm{d} t} = 1

       \frac{\mathrm{d} d}{\mathrm{d} t} = r

     <em>  The rate of the equation is r when r is a constant</em>

<em>        </em>

5 0
3 years ago
Simplify the expression.
denis23 [38]

Answer:

option d

Step-by-step explanation:

\sf \boxed{a^m*a^n = a^{m+n}\\\\}

\sf \left(\frac{m^{-1}m^{5}}{m^{-2}} \right)^{-3} =\left(\dfrac{m^{-1+5}}{m^{-2}}\right)^{-3}

                 \sf = \left(\dfrac{m^4}{m^{-2}}\right)^{-3}\\\\

\boxed{\dfrac{a^{m}}{a^{n}}=a^{m+n}}

                    \sf = \left(m^{4-[-2]}\right)^{-3}\\\\      =\left(m^{4+2}\right)^{-3}\\\\       = \left(m^6\right)^{-3}\\\\

\boxed{(a^{m})^n=a^{m*n}}

                    \sf= m^{6*(-3)}\\\\    = m^{-18}

\boxed{a^{-m}=\dfrac{1}{a^m}}

                    \sf=\dfrac{1}{m^{18}}

8 0
2 years ago
Find the perimeter of the polygon defined by the coordinates (5, 12), (12, 0), (0, 0), and (-4, 12). (Round to nearest tenth) A)
zavuch27 [327]
It would be b...........
8 0
3 years ago
Read 2 more answers
The product of the least and greatest of three consecutive negative odd integers is 221. Find the three integers.
Sonja [21]

Answer:

Step-by-step explanation:

Square Root of 225 is 15 (with -15 also it would work but let’s stick to positive root)

Now, the 1st Odd Number is 15 -2 = 13 and the 3rd Odd Number is 15 + 2 = 17.

The required Numbers are 13 and 17.

This works for 3 consecutive Even Numbers also.

Why does it work?

Because, if we have 3 numbers to be a-2, a and a+2 (Doesn’t really matter if a is positive or negative)

(a-2)*(a+2) = a^2 - 4

So, you see adding 4 to the Product of the 1st Number and the 3rd Number (a^2 - 4 + 4 = a^2) gives you the square of the Middle Number, which is a^2!

7 0
3 years ago
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