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lord [1]
3 years ago
9

Triangles for which two sides and angle opposite one of them are known ssa are reffered to as the

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0
Ambiguous case
Source:
http://www.1728.org/trigtut2.htm
Scroll down to ambiguous case


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Lorico [155]

Answer:

a = 10; a = 2

Step-by-step explanation:

Step 1: Use the Pythagorean theorem to solve this equation

    1. Orignal eqaution: (a + 2)² + (a - 5)² = (a + 3)²

    2. Expand (a + 2)² + (a - 5)² which will give us 2a² - 6a + 29

    3. Expand (a + 3)² giving us a² + 6a + 9

    4. Simplified equation: 2a² - 6a + 29 = a² + 6a + 9

Step 2: Subtract 9 from both sides

    1. 2a² - 6a + 29 - 9 = a² + 6a + 9 - 9

    2. Simplify: 2a² - 6a + 20 = a² + 6a

Step 3: Subtract 6a from both sides

    1. 2a² - 6a + 20 - 6a = a² + 6a - 6a

    2. Simplify: 2a² -12a + 20 = a²

Step 4: Subtract a2 from both sides

    1. 2a² - 12a + 20 - a² = a² - a²

    2. Simplify: a² - 12a + 20 = 0

Step 5: Use the quadratic formula to solve for a

    1. Quadratic formula: a = -b += √b² - 4ac/2a

    2. Plug in the correct values: a = -(-12) += √(-12)² + 4(1)(20)/2(1)

    3. Simplify the numerator and denominator: 12 += 8/2

    4. Final equation: a = 12 - 8/2  or a = 12 + 8/2

    5. Hence, the answer is 10 or 2

4 0
2 years ago
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