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3 years ago

Substance abuse is an _____ coping mechanism.

Computers and Technology

1 answer:

hichkok12 [17]3 years ago

7 0

Mental coping mechanism.

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To change a selected shape’s height or width to a specific value, type the value in the Height or Width text boxes on the

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Are you trying to change the shape of an item within your program by entering the values into text boxes that become variables?

What language are you using?

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4 years ago

How long will it take to transfer 1GB data on USB 2.0, on USB 3.0

cupoosta [38]

Answer:

Have a great day, Here is the answer to your question:

It will take around 18 seconds

Explanation:

So in principle 1GB of data to be uploaded running at peak speed is suggested to take around 18 seconds but in fact, DCD test results show USB 2.0 takes 3 minutes 18 seconds to complete a 1GB switch. Whereas USB 3.0 can accommodate up to 5gbps of data transferred-more than 10 times faster than its predecessor.

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3 years ago

A network is a group of two or more computers or devices connected together. To be able to connect, they each need a

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D. Internet service protocol (isp)

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3 years ago

Read 2 more answers

For a panoramic photograph, you will more than likely want to control the exposure of the photograph yourself rather than lettin

Ronch [10]

When shooting panoramic you would want to control the exposure yourself, much rather than the camera..... A panoramic is one big picture correct, so you would want all of them to be the same exposure level, now some cameras may lock on, and others may not......your correct answer would be TRUE does this make sense?

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4 years ago

Given a sorted array of integers created on the heap, its size and a new integer, design a function which will enlarge the array

Debora [2.8K]

Using the computational language in C++ to write a code that will organize the values in an array through a mathematical condition.

<h3>writing code in C++</h3>

#include <bits/stdc++.h>

using namespace std;

int getIndexInSortedArray(int arr[], int n, int idx)

{

/* Count of elements smaller than current

element plus the equal element occurring

before given index*/

int result = 0;

for (int i = 0; i < n; i++) {

if (arr[i] < arr[idx])

result++;

if (arr[i] == arr[idx] && i < idx)

result++;

}

return result;

}

int main()

{

int arr[] = { 3, 4, 3, 5, 2, 3, 4, 3, 1, 5 };

int n = sizeof(arr) / sizeof(arr[0]);

int idxOfEle = 5;

cout << getIndexInSortedArray(arr, n, idxOfEle);

return 0;

}

See more about C++ at brainly.com/question/12975450

#SPJ1

7 0

2 years ago