Substance abuse is an _____ coping mechanism.

Add the following numbers in abacus 2436+9214

bazaltina [42]

Answer:

the answer is - 11,650

Explanation:

you study abacus too ?

4 0

2 years ago

A combination lock has the following basic properties:

fomenos

Answer:

public class CombinationLock {

private int combinationNumber1 = 0;

private int combinationNumber2 = 0;

private int combinationNumber3 = 0;

CombinationLock(int combinationNumber1, int combinationNumber2, int combinationNumber3){

this.combinationNumber1 = combinationNumber1;

this.combinationNumber2 = combinationNumber2;

this.combinationNumber3 = combinationNumber3;

}

public boolean open(int number1, int number2, int number3){

if(number1 == combinationNumber1 && number2 == combinationNumber2 && number3 == combinationNumber3)

return true;

else

return false;

}

public boolean changeCombo(int number1, int number2, int number3, int newNumber1, int newNumber2, int newNumber3){

if (open(number1, number2, number3)){

combinationNumber1 = newNumber1;

combinationNumber2 = newNumber2;

combinationNumber3 = newNumber3;

return true;

}else

return false;

}

Explanation:

- Three variables are created to hold the combination.

- A constructor is created to set the combination.

- A boolean method called open is created to check if the given numbers are correct, and returns true (otherwise returns false).

- A boolean method method called changeCombo is created to check if given numbers are correct. If they are correct, it assigns new values for the combination and returns true (otherwise returns false).

5 0

2 years ago

write pseudocode to represent the logic of a program that allows the user to enter a value for one edge of a cube. The program c

PilotLPTM [1.2K]

Answer:

prompt("Enter a value for one edge of a cube")

Store user's value into edgeCube

area = 6 * (edgeCube * edgeCube)

volume = edgeCube * edgeCube * edgeCube

print("One side of the cube is: " + edgecube);

print("The area is: " + area)

print("The volume is: " + volume)

8 0

2 years ago

Task 2

USPshnik [31]

4.
3.
1.
5.
2.
I rearranged them so the program would make sense by arranging the interaction in a logical order then placing input statements in between

6 0

2 years ago

Read 2 more answers

. Generate 106 message bits (random binary values (bool/int) ). 2. Generate the corresponding code bits for r = 3, 5. This means

N76 [4]

Answer:

While loops are typically used when you don’t know how many times the loop needs to repeat. The body of the loop will repeat while the condition is true. The logical expression will be evaluated just before the body of the loop is repeated.

Let’s say that we want to find the square root of a number. For some square roots, you’re never going to be exact. Let’s say that we want to find a square root that, when multiplied by itself, is within 0.01 of the square we want. How do we do it? There’s a really old process that we can apply here.

Start by guessing 2.

Compute the guess squared.

Is the guess squared close to the target number? If it’s within 0.01, we’re done. We’ll take the absolute value of the difference, in case we overshoot. (In Python, abs is the absolute value function.)

If it’s not close enough, we divide the target number by our guess, then average that value with our guess.

That’s our new guess. Square it, and go back to Step #3.

Explanation:

7 0

3 years ago