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Alinara [238K]
3 years ago
9

There are 240 coins in a jar, all dimes and quarters. The value of the coins in the jar is $27.60. There are nine times as many

dimes as there are quarters. How many dimes (d ) are in the jar?
Mathematics
1 answer:
SashulF [63]3 years ago
8 0
I believe it is 28 dimes
.25 × 30 = 7.50
.10 × 190 = 19
19 + 7.50 = 26.50
Then, you add 4 more quarters which is 27.50 and the 28 dime makes it 27.60

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Marta_Voda [28]
The first word of the question is cut out of the picture, so we don't exactly know what the assignment is. But we can see that the graph of f(x) will do something weird when x=-3, because the denominator will be zero, and division by zero doesn't even have a definition or meaning. Just for fun, you should go ahead and calculate the numerator when x=-3, and that totally blows your mind, because the numerator is zero too. So you've got. f(-3)= 0/0 , and I can pretty much guarantee that you won't be able to plot that point anywhere on the graph. (I'm pretty sure that f(-3) is actually going to turn out to be -13, but even if I'm correct, you probably haven't learned that little calculus trick yet, so don't worry about it. As far as you're concerned, f(-3) is 0/0, and can't be plotted.)
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4 years ago
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Where is the answer to the expression 3 − 7 located on a horizontal number line?
crimeas [40]
-4 is the correct answer
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4 years ago
Help me please 40 points
ohaa [14]

Answer:

from April to May is 17%

from May to June is 29%

Step-by-step explanation:

24.  

April   30 hr * 6.5 = 195

May  35 * 6.50 = 227.50

percent increase = (new-original)/original

                               (227.5 - 195)/195

                            = 32.50/195

                             .166666

to change from decimal to percent , multiply by 100

  = 16.67%

round to the nearest whole percent

=17%


b) May  35 * 6.50 = 227.50

  June  45* 6.50 = 292.50

percent increase = (new-original)/original

                                = (292.50-227.50)/227.50

                               = 65/227.50

                              =.285714

to change from decimal to percent , multiply by 100

28.57 %

round to the nearest whole percent

29%                            

                             

6 0
3 years ago
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Mariana [72]
-4 for the first one and 2/3 for the second
8 0
4 years ago
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Me voy a comprar una barra de cortinas. Como vivo en un doceavo piso, me interesa saber cuál es la longitud máxima que puedo met
iren2701 [21]

Answer:

The maximum length of the bar I could fit in the elevator is 2.87 meters.

Step-by-step explanation:

<u><em>The question in English is</em></u>

I'm going to buy a curtain rod. Since I live on a twelfth floor, I'm interested in knowing the maximum length I can put in the elevator.

So I take out my pocket tape measure, which only measures up to a meter and I measure the floor which turns out to be a square of 1m x 1m, but for the height it doesn't give.

However, there's a sticker on the lift box that says it has a capacity of 2,500 litres.

With all this information, what is the maximum length of bar that would fit me in the elevator?

step 1

Find the height of the elevator

we know that

The elevator has a capacity of 2,500 litres.

1\ m^3=1,000\ L

so

2,500\ L=2.5\ m^3

The volume of the elevator is given by

V=Bh

where

B is the area of the base

h is the height of the elevator

we have

B=(1)(1)=1\ m^2\\V=2.5\ m^3

substitute

2.5=(1)h\\h=2.5\ m

step 2

Find the diagonal of the base of the elevator

Let

d ---> diagonal of the base of the elevator

Applying the Pythagorean Theorem

d^2=b^2+b^2

substitute

d^2=1^2+1^2

d=\sqrt{2}\ m

step 3

Find the diagonal of the rectangular prism (elevator)

Let

D ----> diagonal of the rectangular prism

d ---> diagonal of the base of elevator

h ----> height of the elevator

Applying the Pythagorean Theorem

D^2=d^2+h^2

substitute

D^2=(\sqrt{2})^2+2.5^2

D^2=8.25\\D=2.87\ cm

therefore

The maximum length of the bar I could fit in the elevator is 2.87 meters.

3 0
3 years ago
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