Solve for z, wz-4/ 5z
1 answer:
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<h3>Answer: (a - 1)(2a² + a + 2)</h3>
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Explanation:
Use the rational root theorem to determine this list of possible rational roots: 1, -1, 1/2, -1/2
Plug each possible root one at a time into the original expression given. If the simplified result is 0, then that possible root is an actual root.
If we tried say a = -1, then,
2a³-a²+a-2 = 2(-1)³-(-1)²+(-1)-2 = -6
The result is not zero, so a = -1 is not an actual root.
But if we tried say a = 1, then,
2a³-a²+a-2 = 2(1)³-1²+1-2 = 0
We get 0 so a = 1 is an actual root. I'll let you try the other values, but you should find that a = 1 is the only rational root.
Since a = 1 is a root, this makes (a-1) to be a factor.
From here, use either synthetic or polynomial long division to determine the other factor. Refer to the diagram below for each method.
Regardless of which method you pick, the quotient is 2a² + a + 2 which is the other factor needed. The remainder of 0 tells us we have (a-1) as a factor. For more information, check out the remainder theorem.
Should be simple:
Let's take this one at a time.
2x(x-3y)
You'd get:
for the first one.
2nd one:
5y(x-3y)
you'd get:
Put them both together:
Combine like terms.
Your Answer:
Let's take this one at a time.
2x(x-3y)
You'd get:
for the first one.
2nd one:
5y(x-3y)
you'd get:
Put them both together:
Combine like terms.
Your Answer: