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riadik2000 [5.3K]
3 years ago
10

In high school Matt grew from weighing 95 pounds to 162 pounds. What was Matt's change in weight during high school

Mathematics
1 answer:
malfutka [58]3 years ago
4 0
Matt's change of weight is 62 pounds

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cestrela7 [59]

Answer:

242

Step-by-step explanation:

7(6*6)-10

7(36)-10

252-10

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7 0
4 years ago
Lim x--&gt; 0 (e^x(sinx)(tax))/x^2
Tom [10]

Make use of the known limit,

\displaystyle\lim_{x\to0}\frac{\sin x}x=1

We have

\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)

since \tan x=\dfrac{\sin x}{\cos x}, and the limit of a product is the same as the product of limits.

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\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1

so the overall limit is 1.

4 0
3 years ago
HELP WILL GIVE BRAINLIEST
Juli2301 [7.4K]

Answer:

6

Step-by-step explanation:

Follow 1 hour on the y axis to where it meets the line of best fit. In this case it is about 6 puzzles.

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3 years ago
How can you prove:<br><br> secθ = cscθtanθ
zavuch27 [327]

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3 years ago
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Sati [7]

Solution

For this case we can use the following formula:

A=P(1+\frac{r}{n})^{nt}

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t= 4 years

Replacing we got:

A=400800(1+\frac{0.055}{4})^{4\cdot4}=498679.58

then the interest would be:

I=A-P=498679.58-400800=97879.58

4 0
1 year ago
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