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3 years ago

In high school Matt grew from weighing 95 pounds to 162 pounds. What was Matt's change in weight during high school

Mathematics

1 answer:

malfutka [58]3 years ago

4 0

Matt's change of weight is 62 pounds

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What is the value of<br>7x2 - 10, when x = 6?<br>

cestrela7 [59]

Answer:

242

Step-by-step explanation:

7(6*6)-10

7(36)-10

252-10

=242

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4 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

HELP WILL GIVE BRAINLIEST

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

Follow 1 hour on the y axis to where it meets the line of best fit. In this case it is about 6 puzzles.

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3 years ago

How can you prove:<br><br> secθ = cscθtanθ

zavuch27 [327]

$\sec \theta=\csc \theta\tan \theta\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\sin \theta}\cdot\dfrac{\sin \theta}{\cos \theta}\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\cos \theta}$

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3 years ago

Mathew deposits 400800.00 kina with the bank which offers 5½% interest per annum. calculate the interest earned after four years

Sati [7]

Solution

For this case we can use the following formula:

$A=P(1+\frac{r}{n})^{nt}$

Where:

P= 400800 = present value

A= future value

r= 0.055 interest rate

n= 4, number of times that the interest is compund in a year (quarterly)

t= 4 years

Replacing we got:

$A=400800(1+\frac{0.055}{4})^{4\cdot4}=498679.58$

then the interest would be:

$I=A-P=498679.58-400800=97879.58$

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1 year ago