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Bas_tet [7]
3 years ago
8

The nose of an ultralight plane is pointed south, and its airspeed indicator shows 28 m/s . the plane is in a 18 m/s wind blowin

g toward the southwest relative to the earth.
Physics
1 answer:
leva [86]3 years ago
6 0
<span>Here I think you have to find the velocity in x and y components where x is east and y is north
 So as air speed indicator shows the negative speed in y component and adding it in
  air speed while multiplying with the direction component we will get the velocity as velocity is a vector quantity so direction is also required
 v=-28 m/s y + 18 m/s (- x/sqrt(2) - y/sqrt(2))
 solving
  v= -12.7 m/s x-40.7 m/s y
 if magnitude of velocity or speed is required then
  speed= sqrt(12.7^2 + 40.7^2)
 speed= 42.63 m/s
 if angle is asked
  angle = arctan (40.7/12.7)
 angle = 72.67 degrees south of west</span>
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Explain an example of how energy is transferred from one form to another
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read the explanation

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8 0
3 years ago
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a train engineer started the train from a standstill and sped up to 5 meters per second, she then rounded a corner at a constant
olasank [31]

for acceleration we can define that rate of change in velocity is know as acceleration

So whenever velocity of train is changing with time we can say train is accelerating

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so here the train is accelerated first time

Then on straight path its speed changed from 5 m/s to 10 m/s so here train gets accelerated second time

After this train chugged around a curve with same speed 10 m/s

SO here since train is moving in curve so here its direction of velocity is continuously changing and this type of acceleration is known as centripetal acceleration

SO this is accelerated Third time

Then its speed decreases and it comes to speed of 5 m/s from 10 m/s

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Then finally train comes to stop so again its speed changed from 5 m/s to 0

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3 0
2 years ago
The displacement vector from your house to the library is 520 m long, pointing 40 ∘ north of east.What are the x-component (x-ax
Alexeev081 [22]

Answer:

398.3 m, 334.2 m

Explanation:

The magnitude of the displacement vector is

v = 520 m

And its direction is

\theta=40^{\circ}

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The x-component of this vector is given by:

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7 0
3 years ago
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