Answer:
Frequencia = 1.25 Hz
Explanation:
<u>Dados los siguientes datos;</u>
- Velocidad = 50 m/s
- Longitud de onda = 40 metros
Para encontrar la frecuencia de la onda;
Matemáticamente, la velocidad de una onda viene dada por la fórmula;
Haciendo de la frecuencia el tema de la fórmula, tenemos;
Sustituyendo en la fórmula, tenemos;
<em>Frequencia = 1.25 Hz</em>
<h2>Answer:</h2>
The refractive index is 1.66
<h2>Explanation:</h2>
The speed of light in a transparent medium is 0.6 times that of its speed in vacuum
.
Refractive index of medium = speed of light in vacuum / speed of light in medium
So
RI = 1/0.6 = 5/3 or 1.66
Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.
- Acceleration is the measure of how quickly a body's velocity varies with regard to time, and constant acceleration occurs when a body's velocity changes proportionately over a period of time, or at a constant rate. It measures in m/s2.
- It is claimed that a body has continual positive acceleration when it begins to move with an initial velocity of zero and gradually increases to a positive value over time.
- Constant positive acceleration is demonstrated by a ball falling freely in a vertical direction.
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It would be the lithosphere
The distance from the 2.0 kg mass at which a string should be attached to balance the rod is 0.67 m.
<h3>What is distance?</h3>
Distance can be defined as the horizontal length between two points.
To calculate the distance at which the string must be attached to balance the rod, we use the formula below.
Formula:
- m₁gx = m₂g(1.2-x)................. Equation 1
From the question,
Given
- m₁ = 2.0 kg
- m₂ = 2.5 kg
- x = Distance of the string from the 2.0 kg mass
- g = Acceleration due to gravity.= 9.8 m/s²
Substitute these values into equation 1
- 2(9.8)(x) = 2.5(9.8)(1.2-x)
Solve for x
Collect like terms
- 19.6x+24.5x = 29.4
- 44.1x = 29.4
- x = 29.4/44.1
- x = 0.67 m
Hence, the distance from the 2.0 kg mass at which a string should be attached to balance the rod is 0.67 m.
Learn more about distance here: brainly.com/question/17273444