To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.
Planet gravitational force
![F_p = 6*10^{22}N](https://tex.z-dn.net/?f=F_p%20%3D%206%2A10%5E%7B22%7DN)
![F_p = \frac{GMm}{R^2}](https://tex.z-dn.net/?f=F_p%20%3D%20%5Cfrac%7BGMm%7D%7BR%5E2%7D)
![F_p = 9*10^{22}N](https://tex.z-dn.net/?f=F_p%20%3D%209%2A10%5E%7B22%7DN)
Distance between planet and star
![r = \frac{R}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7BR%7D%7B2%7D)
Gravitational force is
![F = \frac{GMm}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7BGMm%7D%7Br%5E2%7D)
Applying the new distance,
![F = \frac{GMm}{(\frac{R}{2})^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7BGMm%7D%7B%28%5Cfrac%7BR%7D%7B2%7D%29%5E2%7D)
![F = 4\frac{GMm}{R^2}](https://tex.z-dn.net/?f=F%20%3D%20%204%5Cfrac%7BGMm%7D%7BR%5E2%7D)
Replacing with the previous force,
![F = 4F_p](https://tex.z-dn.net/?f=F%20%3D%204F_p)
Replacing our values
![F= 4(9*10^{22}N)](https://tex.z-dn.net/?f=F%3D%204%289%2A10%5E%7B22%7DN%29)
![F = 36*10^{22}N](https://tex.z-dn.net/?f=F%20%3D%2036%2A10%5E%7B22%7DN)
Therefore the magnitude of the force on the star due to the planet is ![36*10^{22}N](https://tex.z-dn.net/?f=36%2A10%5E%7B22%7DN)
Answer:
Explanation:
The forces compare together as a result of the fact that the force exerted by that of the ball and the force exerted by that of the wall both have the same magnitude.
Answer:
1.15*10^-7 N/m²
Explanation:
Radiation pressure is the pressure exerted on any surface, as a result of the exchange of momentum between the object and its electromagnetic field.
The formula to calculate radiation pressure on a perfect absorber is
P = s/c, where
P = radiation pressure
s = intensity of light
c = speed of light
Now, on substituting the values and plugging it into the equation, we have
P = 34.5 / 3*10^8
P = 1.15*10^-7 N/m²
therefore, radiation pressure is found to be 1.15*10^-7 N/m²
F=-ks
F=-(390)(.45)
F=-175.5 N
Work=force x displacement
Work= 175.5(0.45)
Work= 78.98 J
Work = ∆E =78.98 J
Answer=79J (first option)