Answer:
Ohm's Law
Explanation:
The Ohm's law is a relation between voltage, current and resistance:

If you dont know the current and know the power circulating in the circuit, you can use the relation between power, voltage and resistance:

There is no effect on earth's orbit due to similar force of gravity of black hole.
<h3> How would Earth's orbit change?</h3>
If our Sun was replaced with a black hole having the same mass, Earth's orbit will not changed because of the same force of gravitation of balck hole on earth. Due to this replacement, Earth's temperature will change because balck hole is not too hot like sun.
So we can conclude that there is no effect on earth's orbit due to similar force of gravity of black hole.
Learn more about sun here: brainly.com/question/15837114
Answer:
Option D.
Explanation:
Methods of charging:
1. By friction: when two materials of different electro-negativities rub against each, electrons transfer from one material to another.
2. By induction: When a charged body is brought near an uncharged body, the later gets polarized.
3. By conduction: when electrons from one body to another uncharged while contact, it is known as charging by conduction.
Here, a flower is analogous to an electron. A box of candy is positive charge. A bouquet of flowers is like a charged body which is brought near an uncharged body. It induces charge on ti it by causing it to transfer electron to another.
Thus, option D is correct.
Answer:

Explanation:
As we know that the distance moved by the car is given 300 km
first it move for 120 km with speed
v = 100 km/h
so the time taken by car to move this distance is



Now it moves next 43.0 km with speed 42 km/h
so the time taken by it is given as


now total time of journey is

time remaining to cover the last part of journey is

now the remaining distance is

so the speed of the car is given as


Answer:
e. 27 rho.
Explanation:
The density of an object, assumed constant, is defined as the relationship between the mass and the volume.
If the object is compressed in such a way that the diameter is reduced to 1/3, this means, that the radius will be reduced in the same proportion.
Now, if the mass remains the same (the compression can't change it) , the volume (assumed to be a perfect sphere) will be reduced also:
V₀ = 4/3*π*r³
Vf= 4/3*π*(r/3)³ = 4/3*π*(r³/27) = V₀/27
As the volume is in in the denominator of the expression for density, this means that the new density will be equal to 27 times the original one:
ρ₀ = m/ V₀
ρ₁ = m/ V₁ = m/ (V₀/27) = 27* (m/V₀) = 27*ρ₀