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3 years ago

Coulomb’s Law relates which of the following?

2 answers:

8 0

The answer is "The force between two charges and the distance separating them".

Coulomb's Law is written as:

$F=k \frac{q_1q_2}{r^2}$

In which $F$ is the force felt between two charges, $q_1$ is the charge of one particle, $q_2$ is the charge of the other particle, $r$ is the distance separating them, and $k$ is a constant.

trasher [3.6K]3 years ago

6 0

Coulomb’s Law states the force between two charges
in terms of the magnitude of the charges and the distance
between them.

You might be interested in

A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the

alexandr402 [8]

Answer:

r=6.05km/hr

z=59.1 degree to the horizontal

Explanation:

A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the south relative to the ground. What is the bird's velocity relative to the ground? State your answer to one decimal place

can be solved using pythagoras theorem

r^2=o^2+a^2

r^2=5.2^2+3.1^2

r^2=36.65

r=6.1km/hr is te birds velocity relative to the ground

tanz=5.2/3.1

z=tan^-1(5,2/3.1)

z=59.1 degree to the horizontal

7 0

3 years ago

Read 2 more answers

The barricade at the end of a subway line has a large spring designed to compress 2.00 m when stopping a 1.10 ✕ 105 kg train mov

Mrac [35]

Answer:

(a) k = 1684.38 N/m = 1.684 KN/m

(b) Vi = 0.105 m/s

Explanation:

(a)

First, we find the deceleration of the car. For that purpose we use 3rd equation of motion:

2as = Vf² - Vi²

a = (Vf² - Vi²)/2s

where,

a = deceleration = ?

Vf = final velocity = 0 m/s (since, train finally stops)

Vi = Initial Velocity = 0.35 m/s

s = distance covered by train before stopping = 2 m

Therefore,

a = [(0 m/s)² - (0.35 m/s)²]/(2)(2 m)

a = 0.0306 m/s²

Now, we calculate the force applied on spring by train:

F = ma

F = (1.1 x 10⁵ kg)(0.0306 m/s²)

F = 3368.75 N

Now, for force constant, we use Hooke's Law:

F = kΔx

where,

k = Force Constant = ?

Δx = Compression = 2 m

Therefore.

3368.75 N = k(2 m)

k = (3368.75 N)/(2 m)

k = 1684.38 N/m = 1.684 KN/m

(c)

Applying Hooke's Law with:

Δx = 0.6 m

F = (1684.38 N/m)(0.6 m)

F = 1010.62 N = 1.01 KN

(b)

Now, the acceleration required for this force is:

F = ma

1010.62 N = (1.1 kg)a

a = 1010.62 N/1.1 x 10⁵ kg

a = 0.0092 m/s²

Now, we find initial velocity of train by using 3rd equation of motion:

2as = Vf² - Vi²

a = (Vf² - Vi²)/2s

where,

a = deceleration = -0.0092 m/s² (negative sign due to deceleration)

Vf = final velocity = 0 m/s (since, train finally stops)

Vi = Initial Velocity = ?

s = distance covered by train before stopping = 0.6 m

Therefore,

-0.0092 m/s² = [(0 m/s)² - Vi²]/(2)(0.6 m)

Vi = √(0.0092 m/s²)(1.2 m)

Vi = 0.105 m/s

4 0

3 years ago

During a total lunar eclipse, where is the Moon located?

krok68 [10]

During a total lunar eclipse, the Moon located in the umbra. The answer is letter A. For a total lunar eclipse to occur, the Sun, Earth and Moon must be aligned in a straight line. The Earth’s umbra complete covers the Moon. The earth’s umbra is about 870,000 miles wide.

5 0

3 years ago

What is a mixture of rock and mineral fragments, organic matter, air, and water called?

Gekata [30.6K]

The answer should be soil

7 0

3 years ago

A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is

ivanzaharov [21]

anwser will be

F = ma

where

F = force exerted on the bullet
m = mass of the bullet = 5 gm (given) = 0.005 kg.
a = acceleration of the bullet

Substituting appropriately,

F = 0.005a --- call this Equation 1

Next working equation is

Vf^2 - Vo^2 = 2as

where

Vf = velocity of the bullet as it leaves the muzzle = 326 m/sec (given)
Vo = initial velocity of bullet = 0
a = acceleration of bullet
s = length of the rifle's barrel

Substituting appropriately,

326^2 - 0 = 2(a)(0.83)

a = 64,022 m/sec^2

the anwser will be
Substituting this into Equation 1,

F = 0.005(64,022)

F =320.11 Newtons

Hope this helps.

8 0

3 years ago