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Greeley [361]
3 years ago
15

Describe different types of force in nature at least five​

Physics
2 answers:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Contact Forces Action-at-a-Distance Forces

Frictional Force Gravitational Force

Tension Force Electrical Force

Normal Force Magnetic Force

Air Resistance Force

sineoko [7]3 years ago
3 0

Weathering, Erosion,  deposition, acid rain, precipitation

Explanation:

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A coiled telephone cord forms a spiral with 90.0 turns, a diameter of 1.30 cm, and an unstretched length of 57.0 cm. Determine t
Vinvika [58]

Answer:

2.36 μ H

Explanation:

Given,

Number of turns= 90

diameter = 1.3 cm = 0.013 m

unscratched length = 57 cm  = 0.57 m

Area, A = π r²

            = π x 0.0065² = 1.32 x 10⁻⁴ m²

 we know,

   L = \dfrac{\mu_0N^2A}{l}

   L = \dfrac{4\pi \times 10^{-7}\times 90^2\times 1.32\times 10^{-4}}{0.57}

    L = 2.36 μ H

Hence, the inductance of the unstretched cord is equal to 2.36 μ H

8 0
3 years ago
Susan is making an electromagnet in her science class today. First, she takes a nail and winds coils of copper wire around it th
matrenka [14]

Answer:

Electrical

Explanation:

She uses a battery, which is electrical.

It doesn't operate using chemicals, heat, or light

5 0
3 years ago
Read 2 more answers
The speed at which a light aircraft can take off is 120 km/h. (A) What is the minimum constant acceleration required for the pla
kondor19780726 [428]

Answer:

A) a = 2.31[m/s^2]; B) t = 14.4 [s]

Explanation:

We can solve this problem using the kinematic equations, but firts we must identify the data:

Vf= final velocity = take off velocity = 120[km/h]

Vi= initial velocity = 0, because the plane starts to move from the rest.

dx= distance to run = 240 [m]

v_{f} ^{2} =v_{i} ^{2}+2*g*dx\\where:\\v_{f}=120[\frac{km}{h} ]*\frac{1hr}{3600sg} * \frac{1000m}{1km} =33.33[m/s]\\\\Replacing\\33.33^{2}=0+2*a*(240)\\ a=\frac{11108.88}{2*240}\\  a=2.31[m/s^2]\\

To find the time we must use another kinematic equation.

v_{f} =v_{i} +a*t\\replacing:\\33.33=0+(2.31*t)\\t=\frac{33.33}{2.31}\\ t=14.4[s]

7 0
3 years ago
When a 0.350-kg package is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The package is now di
AleksandrR [38]

To solve the problem it is necessary to use the concepts related to the calculation of periods by means of a spring constant.

We know that by Hooke's law

F=kx

Where,

k = Spring constant

x = Displacement

Re-arrange to find k,

k= \frac{F}{x}

k= \frac{mg}{x}

k= \frac{(0.35)(9.8)}{12*10^{-2}}

k = 28.58N/m

Perioricity in an elastic body is defined by

T = 2\pi \sqrt{\frac{m}{k}}

Where,

m = Mass

k = Spring constant

T = 2\pi \sqrt{\frac{0.35}{28.58}}

T = 0.685s

Therefore the period of the oscillations is 0.685s

4 0
2 years ago
A piano emits frequencies the range from a low of about 28 Hz to a high of about 4200 Hz. Find the range of wavelengths in air a
Step2247 [10]
V=wave velocity , <span>f= frequency, </span><span>λ=wavelength </span>
<span>Use it to find corresponding wavelengths for</span><span> f=28 Hz </span>
<span>λ= v/f= 337/28=12.036 m 
</span>
<span>for f=4200 Hz </span>
<span>λ= v/f=337/4200= 0.08 m </span>
<span>So max. wavelength is 12.036 m and </span>
<span>Min Wavelength is 0.08 m </span>
<span>So the range is between .08 m and 12.036 m
</span>Hope this helps. 
4 0
3 years ago
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