9.6 boards is what i got when i divided the numbers
Answer:
5 & 2
Step-by-step explanation:
10 / 2 = 5
10 / 5 = 2
Answer:
−1,−4,−9,−14,-19,-24,-29,-34,-39,-44,-49,-54
Step-by-step explanation:
Sum is 3 then 5
Answer:
<h2>
TO FIND THE AREA OF A RECTANGLE, THAT IS L×B <em>O</em><em>R</em><em> </em>L× W (WIDTH/BREADTH) IS THE SAME THING. KEEP THAT IN MIND. SO : 90FT × 150FT. = 13500FTSQ. </h2>
<h2>
BUT WE ARENT FINISHED . YOU NEED TO FIND THE AREA OF BOTH SEMICIRCLES (SEMI MEANS HALF) , SO HENCE, THE AREA OF BOTH HALF SEMICIRCLES. </h2>
<h2>
THAT IS : PIRSQUARED. PI×R×R. </h2><h2>
THE RADIUS IS UNKNOWN. SO WE WILL USE THE DIAMETER TO FIND THE RADIUS SINCE THE DIAMETER IS <em><u>T</u></em><em><u>W</u></em><em><u>I</u></em><em><u>C</u></em><em><u>E</u></em><em><u> </u></em><em><u>T</u></em><em><u>H</u></em><em><u>E</u></em><em><u> </u></em><em><u>R</u></em><em><u>A</u></em><em><u>D</u></em><em><u>I</u></em><em><u>U</u></em><em><u>S</u></em><em><u>.</u></em><em><u> </u></em></h2><h2>
THAT IS : 90÷2 , THAT IS = 45. </h2>
SO WE KNOW THE RADIUS OF EACH SEMI CIRCLE IS 45. SO NOW :
<h2>
PIRSQUARED = PI × R×R </h2><h2>
3.14 × 45×45 OR 45SQUARED.</h2>
<h2>
THAT IS : 6,358.5 FT SQUARED. </h2>
<h2>
NOW 6,358.5FT SQ IS ONLY THE AREA OF <em><u>O</u></em><em><u>N</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>E</u></em><em><u>M</u></em><em><u>I</u></em><em><u>C</u></em><em><u>I</u></em><em><u>R</u></em><em><u>C</u></em><em><u>L</u></em><em><u>E</u></em><em><u>.</u></em><em><u> </u></em> SO NOW WE KNOW THAT BOTH SEMICIRCLES HAVE A AREA OF 6,358.5 FT SQ.</h2>
<h2>
WE WILL ADD : 6,358.5 + 6,358.5 = 12,717.</h2>
YOU ARE GOING TO ADD THE AREA OF BOTH HALF CIRCLES TO THE AREA OF THE RECTANGLE.
= 26,217FT SQ.
<h2>
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9514 1404 393
Answer:
(9√3 -3π/2) ft^3 ≈ 10.88 ft^3
Step-by-step explanation:
The area of the hexagon is given by the formula ...
A = (3/2)√3·s^2 . . . . for side length s
The area of the hexagonal face of this solid is ...
A = (3/2)√3·(2 ft)^2 = 6√3 ft^2
__
The area of the circular hole in the hexagonal face is ...
A = πr^2
The radius is half the diameter, so is r = (2 ft)/2 = 1 ft.
A = π(1 ft)^2 = π ft^2
Then the area of the "solid" part of the face of the figure is ...
A = (6√3 -π) ft^2
__
The volume is ...
V = Bh . . . . . where B is the area of the base of the prism, and h is its height
V = ((6√3 -π) ft^2)(3/2 ft) = (9√3 -3π/2) ft^3 ≈ 10.88 ft^3