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3 years ago

Which is the completely factored form of 3x^2-12x-15

Mathematics

1 answer:

Luba_88 [7]3 years ago

6 0

Find the GCF (Greatest Common Factor)

GCF = 3

Factor out the GCF ( Write the GCF first. Then, in parentheses, divide each term by the GCF)

3(3x^2/3 + -12x/3 - 15/3)

Simplify each term in parentheses

3(x^2 - 4x - 5)

Factor x^2 - 4x - 5

3(x - 5)(x + 1)

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irina [24]

Option D:

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Solution:

Given expression is $\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$ .

To find the product of the expression:

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$

Multiply each term of the first term with each term of the 2nd term.

$=y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)$

Using the exponent rule: $a^m \cdot a^n = a^{m+n}$

$=\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)$

$=8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7$

Arrange the terms with same power.

$=8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7$

$=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Hence option D is the correct answer.

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

6 0

3 years ago

Y=3x, is this in standard form? And if not can i get an explanation on why not?

kodGreya [7K]

Answer: i would say no

Step-by-step explanation:

To write a linear equation in standard form, move each variable term to the left side of the equation and simplify.

Ax+By=C

Since x

is on the right side of the equation, switch the sides so it is on the left side of the equation.

3x=y

Move y

to the left side of the equation because it contains a variable.

3x−y=0

3 0

3 years ago

Read 2 more answers

Select all the correct graphs.

Anika [276]

Answer:

garoph 1 and 2 hope this helps

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and

tia_tia [17]

$p=501\cdot503\cdot\cdots\cdot597$

$q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601$

So we have $q=359,999p$ . Then

$\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q$

and the answer is D.

4 0

3 years ago

Hello can you please help posted picture of question

lesya692 [45]

We know that

the graphic has two intervals
x>1------> (1,∞)
equation of second order
and
x<=1------> (-∞, 1]
equation of a line

therefore
The only option that meets these requirements is option A

the answer is
the option A

3 0

3 years ago