Please Help!!!! How do you work this out. If U is between T and B, find the value of x and the lengths of the segments.

Simplify <br> −5x^4(−3x^2+4x−2)

malfutka [58]

112 me dió a eso mira haber si es si no trate.

6 0

3 years ago

It would be nice if anyone could help<br>

Allushta [10]

<h3>Answer: x = 140 (choice C)</h3>

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Explanation:

Focus on the upper semicircle. It's composed of the arc pieces that are 30 degrees, x degrees, and y degrees. The y is the missing unmarked portion of the upper semicircle.

Subtract the 30 and y degree angles, divide by 2, and set that result equal to 10. This will help us solve for y

(30-y)/2 = 10

30-y = 10*2

30-y = 20

-y = 20-30

-y = -10

y = 10

Because the 30, x and y arcs form a semicircle, this must mean the three arcs add to 180 degrees

30+x+y = 180

30+x+10 = 180

x+40 = 180

x = 180-40

x = 140

5 0

3 years ago

Round to the nearest tenth.

sammy [17]

Answer:

$c=9.3\ units$

Step-by-step explanation:

step 1

Find the measure of angle A

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

$A+B+C=180^o$

substitute the given values

$A+110^o+30^o=180^o\\A=40^o$

step 2

Find the length side c

Applying the law of sines

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{12}{sin(40^o)}=\frac{c}{sin(30^o)}$

solve for c

$c=\frac{12}{sin(40^o)}sin(30^o)$

$c=9.3\ units$

4 0

4 years ago

Y = 6x+ 3<br> y = - 6x + 4<br> These lines are...<br> Neither?<br> Parallel?<br> Perpendicular?

Yuki888 [10]

Answer:

i dont get it i would help

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

ppose we are testing a new shampoo to see if it makes hair grow faster. We knowthat the average rate of hair growth is 0.5 inche

alukav5142 [94]

Answer:

Type II error occurred

Step-by-step explanation:

It is given that a new shampoo is being tested to determine whether the hair grows faster by using this shampoo.

It is known that hair grow at 0.5 inches per month at average.

The hypothesis are,

Null hypothesis, $H_0: \mu=0.5$

Alternate hypothesis, $H_1: \mu>0.5$

But it is known that :

Type $I$ error occurs when rejecting the null hypothesis when the null hypothesis is true actually.

Type $II$ error occurs $\text{when we fail reject the null hypothesis}$ when the null hypothesis is actually false.

Now here since the null hypothesis is not been rejected, type $II$ error had occurred.

6 0

3 years ago