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7nadin3 [17]
4 years ago
11

I need help with this question

Mathematics
1 answer:
Viktor [21]4 years ago
5 0
Y = 4x + 3  ---------(1)
y = -x - 2    ---------(2)

Subtract (2) from (1), you get
0 = 5x + 5
⇒ 5x + 5 = 0
⇒ 5x = -5
⇒ x = -5/5 = -1
y = -(-1) - 2 = -1

Answer is (-1,-1)
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Answer:

Discrete

Step-by-step explanation:

A set can simply be defined as a list of values. There are many different types of sets, some are intervals, others are enumerated numbers. Often, a set composed of values that are listed is referred to as a discrete set. Discrete sets can be a list of information, or "isolated points". Knowing this information, the most logical answer to fill in the blank is "discrete".

"If a set is made up of isolated points and can be written as a list, it is called a <u>discrete</u> set."

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Find the missing side . round the the nearest tenth
lys-0071 [83]

S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}

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7) You have the opposite. You need the adjacent.

Tan=\frac{Opposite}{Adjacent}

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x=\frac{12}{Tan57}

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<h2>7.8</h2><h2 />

8) You have the hypotenuse. You need the Opposite.

Sin=\frac{x}{Hypotenuse}

Sin37=\frac{x}{13}

x = sin37 × 13

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9) You have the hypotenuse. You need the opposite.

Sin=\frac{x}{Hypotenuse}

Sin59=\frac{x}{11}

x = sin59 × 11

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10) You have the hypotenuse. You need the opposite.

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Semmy [17]

Answer:

Period ⇒ 40

Amplitude ⇒ 12

Mid-line ⇒ 32

Step-by-step explanation:

The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40

<u />

The amplitude can be found by using the following:

\frac{1}{2}|max - min|

Our maximum is 44 and our minimum is 20.

\frac{1}{2}|44 - 20|

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\frac{1}{2}(24)

The amplitude is 12

The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)

44 - 12 = 32

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Therefore our mid-line is y = 32

~Hope this helps!~

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