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lys-0071 [83]
3 years ago
11

the function f(x)=40x-80 models the number of visitors a website received x days after it was created. Which is the most appropr

iate domain for function?
Mathematics
1 answer:
goblinko [34]3 years ago
8 0
Hello there!

When finding the domain of a function, the only things you need to watch for are...
1. Variables under even radical signs
2. Variables in the dominator of fractions
3. Logarithms

Since this function is linear, there is nothing that would stop any real number from being part of the domain.

This means that the domain is all real numbers. (-∞,∞)

I hope this helps!
Best wishes:)
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When an object with a momentum of 80 kg ´ m/s collides with an object with a momentum of –100 kg ´ m/s the total momentum after
mojhsa [17]
This is a physics problem.

The law is that the momentum is preserved: total momentum before collsion = total momentum after collision

Momentum before collision = 80 kg.m/s - 100 kg.m/s = -20 kg.m/s

Then answer is b. - 20 kg.m/s
3 0
3 years ago
Do you know what 2/9 x 3 is?
ohaa [14]

Answer:

answer =  \frac{2}{3}

\frac{2}{9}  \times  \frac{3}{1}  \\   =  \frac{6}{9}  =  \frac{2}{3}

7 0
3 years ago
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Find the missing length
pshichka [43]

Answer:

9 yd

Step-by-step explanation:

15 yd - 6 yd = 9 yd

Please mark my answer as brainiest

7 0
3 years ago
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The two circles shown above have radii of 8 in. and 2 in.
algol [13]

Answer:

1/4

Step-by-step explanation:

For the first circle 2 x 2in = 4 to find diameter

4 x 3.14 = 12.56

6in x 2 = 12

12 x 3.14 = 37.68

simplify

12.56/37.68

6.28/18.84

3.14/9.42

So the answer is 1/4 since 3.14 x 2 = 6.28

Also since the radius is 2 times longer

3 0
3 years ago
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Construct a polynomial function with the following properties: third degree, only real coefficients, −3 and 3+i are two of the z
irina [24]

Answer:

\boxed{-3(x+3)(x^2-6x+10)}

Step-by-step explanation:

Hello,

As the polynomial has only real coefficients, it means that 3-i is a zero too, because we apply the Conjugate Zeros Theorem.

It means that we can write the expression as below, k being a real number that we will have to identify.

k(x+3)(x-3-i)(x-3+i)=k(x+3)((x-3)^2-i^2)\\\\=k(x+3)(x^2-6x+9+1)\\\\=k(x+3)(x^2-6x+10)

And for x = 0, y = -90 so we can write

-90=k*3*10, meaning that k=-3

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
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