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VARVARA [1.3K]
3 years ago
13

In percent problems, the term rate refers to the

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
In percentage problems, the term rate refers to the actual percentage itself. Let's look at an example. If you have a principal amount of 1000 and you will be getting a yearly interest of 5%, then the rate is the 5%. We refer to it as the interest rate. So if you are looking for the rate in any percentage problem, then you just have to look for the number that has the percentage symbol. The one with the percentage symbol is always the rate. 
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Jane sells 8 times as many Volvos as Melissa. If the difference in their sales is 35, how many cars did Jane sell?
Usimov [2.4K]
Here we have 2 variables we need to calculate:
x - how many Volvos Jane sold
y - how many Volvos Melissa sold

We write system of equations:
x = 8*y
x - y = 35
------------
8y - y = 35
7y = 35
y = 5
x = 8*5 = 40

Jane sold 40 cars.
8 0
3 years ago
Here's the question. ​
OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is <u>-20</u>.

Step-by-step explanation:

<u>Given</u> :

  • >> If for an A.P, d = -4

<u>To</u><u> </u><u>Find</u> :

  • >> T₂₀ - T₁₅

<u>Using Formula</u> :

General term of an A.P.

\star{\small{\underline{\boxed{\sf{\red{ T_n = a  + (n - 1)d}}}}}}

  • >> Tₙ = nᵗʰ term
  • >> a = first term
  • >> n = no. of terms
  • >> d = common difference

<u>Solution</u> :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{20} = a  + (20 - 1) d}}}

{\dashrightarrow{\sf{ T_{20} = a  + (19)d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19  \times d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19d}}}

{\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a  + 19d}}}}}}

Hence, the value of T₂₀ is a + 19d.

\rule{190}1

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{15}= a  + (15 - 1) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + (14) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14 \times d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14d}}}

{\star{\underline{\boxed{\sf \pink{ T_{15}= a  + 14d}}}}}

Hence, the value of T₁₅ is a + 14d

\rule{190}1

Now, finding the difference between T₂₀ - T₁₅ :

{\dashrightarrow{\pmb{\sf{T_{20} -  T_{15}}}}}

{\dashrightarrow{\sf{(a + 19d) -  (a + 14d)}}}

{\dashrightarrow{\sf{a + 19d -  a  -  14d}}}

{\dashrightarrow{\sf{a - a + 19d -  14d}}}

{\dashrightarrow{\sf{0+ 19d -  14d}}}

{\dashrightarrow{\sf{19d -  14d}}}

{\dashrightarrow{\sf{5 \times  - 4}}}

{\dashrightarrow{\sf{ - 20}}}

{\star \: \underline{\boxed{\sf{\pink{T_{20} -  T_{15} =  - 20}}}}}

Hence, the value of T₂₀ - T₁₅ is -20.

\underline{\rule{220pt}{3.5pt}}

3 0
2 years ago
Which pairs of quadrilaterals can be shown to be congruent using rigid motions?
Misha Larkins [42]

Answer:

1 and 2 are not congruent; 1 and 3 are congruent; 1 and 4 are congruent; 2 and 3 are not congruent; 2 and 4 are not congruent; 3 and 4 are congruent.

Step-by-step explanation:

From the diagram, we can see that the angle measures and side measures of figures 1, 3 and 4 are the same.  This means that these three figures are congruent.  Figure 2, however, is not congruent to any of the other 3.

5 0
3 years ago
Read 2 more answers
HELP ME PLEASE!!
DiKsa [7]
C=A+B
C₄₁= row=4;  column=1
C₄₁=A₄₁+B₄₁         
=2(7)-3(4)
=14-12
=2

Answer: C₄₁=2
5 0
2 years ago
(x-2)=-1/4(x-8) <br> please show steps
RSB [31]

Answer:

(

−

2

)

=

−

1

4

(

−

8

)

(x-2)=\frac{-1}{4}(x-8)

(x−2)=4−1​(x−8)

Solve

1

Eliminate redundant parentheses

(

−

2

)

=

−

1

4

(

−

8

)

−

2

=

−

1

4

(

−

8

)

2

Combine multiplied terms into a single fraction

−

2

=

−

1

4

(

−

8

)

−

2

=

−

1

(

−

8

)

4

3

Distribute

−

2

=

−

1

(

−

8

)

4

−

2

=

−

+

8

4

4

Add

2

2

2

to both sides of the equation

−

2

=

−

+

8

4

−

2

+

2

=

−

+

8

4

+

2

5

Simplify

Add the numbers

=

−

+

8

4

+

2

Solution

=

1

6

5

Step-by-step explanation:

4 0
3 years ago
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