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3 years ago

What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x + y - 1 = 0?

Mathematics

2 answers:

DiKsa [7]3 years ago

8 0

Y=-4x+6
or if you need it in the original format
4x+y-6=0

juin [17]3 years ago

7 0

Answer: The required equation of the line is $4x+y=6.$

Step-by-step explanation: We are given to find the equation of the line that passes through (1, 2) and is parallel to the line whose equation is as follows:

$4x+y-1=0~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

The slope-intercept form of the given line (i) is

$4x+y-1=0\\\\\Rightarrow 4x+y=1\\\\\Rightarrow y=-4x+1,$

where, slope of the line is, m = - 4.

Since parallel lines have equal slopes, so the slope of the new line that passes through the point (1, 2) is

m = - 4.

Therefore, the equation of the line will be

$y-2=m(x-1)\\\\\Rightarrow y-2=-4(x-1)\\\\\Rightarrow y-2=-4x+4\\\\\Rightarrow 4x+y=6.$

Thus, the required equation of the line is $4x+y=6.$

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Answer:

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3 years ago

Factor this polynomial completely x2 + 3x – 18 A. (x-2)(x + 9) B. (x+3)(x-6) оо C. (x - 3)(x+6) D. (x - 3)(x-6)

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Answer:

C. $(x-3)(x+6)$

Step-by-step explanation:

I think the equation meant $x^2+3x-18$ ?

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ONLY if:

$w+v=b\\wv=c$

Start off by finding factors of c, which in this case, -18:

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If one of the numbers is negative then the other number must be positive.

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The only two factors that work are 6 and -3.

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