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Svet_ta [14]
3 years ago
9

What is the correct formula for iron (ii) bromide?

Chemistry
2 answers:
anastassius [24]3 years ago
6 0
FeBr2 (1 iron, 2 bromide)
neonofarm [45]3 years ago
3 0
<span>The formula for iron bromide is FeBr^2 (one iron and 2 bromines)</span>
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If 120.3 mL of water is shaken with oxygen gas at 2.1 atm, it will dissolve 0.0043 g O2. Estimate the Henry's law constant for t
nikklg [1K]

<u>Answer:</u> The Henry's law constant for oxygen gas in water is 1.702\times 10^{-5}g/mL.atm

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{O_2}=K_H\times p_{O_2}

where,

K_H = Henry's constant = ?

C_{O_2} = solubility of oxygen gas = 0.0043g/120.3mL

p_{O_2 = partial pressure of oxygen gas = 2.1 atm

Putting values in above equation, we get:

0.0043g/120.3mL=K_H\times 2.1atm\\\\K_H=\frac{0.0043g}{120.3mL\times 2.1atm}=1.702\times 10^{-5}g/mL.atm

Hence, the Henry's law constant for oxygen gas in water is 1.702\times 10^{-5}g/mL.atm

7 0
3 years ago
The crust and upper mantle make up Earth's ____.
Alekssandra [29.7K]

Answer:

a. the lithosphere

Explanation:

google

7 0
3 years ago
Which of the following numerical expressions gives the number of particles in 2.0 g of Ne?
mojhsa [17]

Answer:

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

Explanation:

Step 1: Data give

Mass of Ne = 2.0 grams

Molar mass of neon = 20.18 g/mol

Number of Avogadro = 6.0 *10^23 /mol

Step 2: Calculate number of moles of neon

Moles Ne = Mass of ne / Molar mass of ne

Moles Ne = 2.0 / 20.18 g/mol

Moles Ne = 0.099 moles

Step 3: Calculate nulber of particles

Number of particles = 6.022*10^23 / mol * 0.099 moles = 5.96 *10^22

Number of particles = 6.022*10^23 * (2.0g/ 20.18g/mol)

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

7 0
3 years ago
Is air a compound mixture or a element.
GenaCL600 [577]

Is air a compound mixture or a element. compound

8 0
4 years ago
Read 2 more answers
Box 1
Alex73 [517]

10g

Explanation:

Box 1, Mass of A = 10g

Box 2, Mass of B = 5g

Box 3, = 1A + 1B

Unknown:

Mass of B that would combine with mass of 20g of A

Solution:

   Mass ratio of A to B:

   \frac{mass of A}{mass of B} = mass ratio

           \frac{10}{5} = mass ratio

        The mass ratio of A to B = 2: 1

Now, number of B that will combine with 20g of A;

       

           \frac{mass of A}{mass of B} = mass ratio

               \frac{20}{mass of B} = \frac{2}{1}

                     Mass of B = 10g

10g of B would combine with 20g of A

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7 0
3 years ago
Read 2 more answers
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