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3 years ago

3.0 cm x 4.0 cm x 1.0 cm[?]cm^3

Chemistry

1 answer:

CaHeK987 [17]3 years ago

4 0

Explanation:

Hi there!!

you asked to multiply these all right,

you can simply multiply it ,

=3cm × 4 cm × 1cm

= 12cm^2×1cm (4×3=12)

= 12cm^3 (12×1=12)

Therefore, theanswer is 12 cm^3.

Hope it helps..

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Why parafin oil use in melting

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Answer:

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3 years ago

What is the molality of an aqueous KCl solution with a mole fraction of KCl, XKCl = 0.175? (The molar mass of KCl = 74.55 g/mol

NARA [144]

Answer:

The molality of the KCl solution is 11.8 molal

Explanation:

Step 1: Data given

Mol fracrion KCl = 0.175

Molar mass KCl = 74.55 g/mol

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mol fraction H2O

mol fraction H2O = 1 - 0.175 = 0.825

Step 3: Calulate mass of H2O

Suppose the total moles = 1.0 mol

Mass H2O = moles H2O * molar mass

Mass H2O = 0.825 * 18.02 g/mol

Mass H2O = 14.87 grams = 0.01487 kg

Step 4: Calculate molality

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Molality KCl = 11.8 molal

The molality of the KCl solution is 11.8 molal

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3 years ago

What is the mass of substance that exactly fills a 247.2 mL container? The density of the substance is 0.81 g/mL. Give the answe

matrenka [14]

Answer:

Explanation:

The density of a substance can be found by using the formula

$Density = \frac{mass}{volume}$

Since we are finding the mass

<h3>mass = Density × volume</h3>

From the question

Density = 0.81 g/mL

volume = 247.2 mL

Substitute the values into the above formula and solve for the mass

mass = 0.81 × 247.2

= 200.232

We have the final answer as

<h3>mass = 200.23 g to 2 decimal places</h3>

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If you have 8.943 L of carbon monoxide gas at SATP, how many moles would it contain?

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3 years ago

3.0 cm x 4.0 cm x 1.0 cm[?]cm^3​

3.0 cm x 4.0 cm x 1.0 cm[?]cm^3