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Blababa [14]
2 years ago
11

The percent yield of a chemical reaction is valuable to many industries. Low percent yields can result in the loss of large amou

nts of money. Which of the following would likely increase the percent yield of a reaction? Check all that apply. Using accurate measurements using pure chemicals performing the reaction under the most ideal conditions adding water to the experiment.
Chemistry
1 answer:
aev [14]2 years ago
7 0

Using accurate measurements, using pure chemicals and performing the reaction under the most ideal conditions is important to get a valuable percent yield.

<h3>How we calculate the percent yield?</h3>

Percent yield of any chemical reaction is define as the ratios of the actual yield to the theoretical yield of the product and multiply by the 100.

To get the high percent yield or actual yield of any reaction, we have to perform the reaction under ideal condition because if we not use the standard condition then we get the low rate of reaction. Reactants should be present in the pure form as impurity make unwanted products and reduce the productivity of main product and accurate amount of reactants also important for the spontaneous reaction.

Hence, options (a), (b) & (c) are correct.

To know more about percent yield, visit the below link:

brainly.com/question/8638404

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How many moles of nitric acid are present in 35.0 ml of a 2.20 M solution?
vodomira [7]

Answer:

There are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

Explanation:

Molarity of the solution = 2.20 M

Molarity=\frac{number\:of\:moles}{Volume\:of\:Solution\:in\:L}\\\\Number\:of\:moles=Molarity\times(Volume\:of\:Solution\:in\:L)\\\\Volume\:of\:Solution=35\:mL=35\times10^{-3}L\\\\Number\:of\:moles=2.20\times35\times10^{-3}=77\times10^{-3}\:moles\:of\:HNO_{3}

Therefore, there are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

8 0
3 years ago
Look at the two question marks between zinc (zn) and arsenic (as). at the time, no elements were known with atomic weights betwe
Thepotemich [5.8K]

<u>Mendeleev </u><u>positioned elements in the periodic table in</u><u> increasing order </u><u>of their atomic numbers, such that </u><u>elements </u><u>having identical chemical properties and characteristics plunge into the </u><u>same group.</u>

What is Mendeleev's periodic table called?

  • In order to represent similarities and patterns in the behavior of elements, Mendeleev created the periodic table, which is an arrangement of elements in an increasing atomic mass order in tablet form.
  • Mendeleev stated that "Element characteristics are a periodic function of their atomic weight" in his renowned periodic law.
  • The Periodic Table of Mendeleev is a table that Mendeleev created to list elements in the order of their atomic weights.

  • Mendeleev discovered that there were two elements with atomic weights between 65.2 and 75 because he found it very satisfying that the properties of the elements were more similar and closer to this level.
  • He also imagined having other elements with possessions similar to those of these other elements.
  • In the periodic table, he left a blank for these two elements until they were finally discovered in their true existence.

Learn more about Mendeleev's periodic table

brainly.com/question/11974961

#SPJ4

3 0
2 years ago
How much milk at 1 degrees Celsius is needed to reduce the temperature of
Kobotan [32]
It’s can go down to 50 degrees soo that can do
8 0
3 years ago
: Citric acid, H3C6H5O7, is a triprotic acid. Consider a buffer system comprising H2C6H5O7 - and HC6H5O7 2- ions. What is the ne
olchik [2.2K]

Answer:

The Net reaction is    

  1.    H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction
  2.    H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH
  3.    HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH  

Explanation:

From the Question we are told that the buffers are

                H_2C_6H_5O_7^ - and  HC_6H_5O_7 ^{ 2-}

When NaOH is added the Net ionic reaction would be

  1.    H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction
  2.    H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH
  3.    HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH  

             

8 0
3 years ago
Read 2 more answers
Please help me out its due tmr :/
lesantik [10]

Answer:

using this for points, did you get the answer because I can try and help?

Explanation:

7 0
3 years ago
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