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viva [34]
3 years ago
10

Check the screenshot for the question. 25 POINTS

Mathematics
1 answer:
svet-max [94.6K]3 years ago
4 0

Answer: Y = -10

Step-by-step explanation:

-x + y = -27

-17 + y = -27

+17 +17

Y = -10

You can also check your work by plugging in the X and Y values and it should equal -27 . So -17 + -10 equals -27.

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Which of the following statements demonstrates the associative property of multiplication? A. 4. (3x6) = (4 x 3) · 6. B 6x4 = 4x
scoray [572]
I hope this helps but it is either d or a because parentheses and another term for multiplication and so is a dot
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3 years ago
Suppose that 5 J of work is needed to stretch a spring from its natural length of 36 cm to a length of 51 cm. (a) How much work
olganol [36]

Answer:

a) 0.6 joules of work are needed to stretch the spring from 41 centimeters to 46 centimeters.

b) The spring must be 5.6 centimeters far from its natural length.

Step-by-step explanation:

a) The work done to stretch the ideal spring from its natural length is defined by the following definition:

W = \frac{1}{2}\cdot k\cdot (x_{f}-x_{o})^{2} (1)

Where:

k - Spring constant, measured in newtons.

x_{o}, x_{f} - Initial and final lengths of the spring, measured in meters.

W - Work, measured in joules.

The spring constant is: (W = 5\,J, x_{o} = 0.36\,m, x_{f} = 0.51\,m)

k = \frac{2\cdot W}{(x_{f}-x_{o})^{2}}

k = \frac{2\cdot (5\,J)}{(0.51\,m-0.36\,m)^{2}}

k = 444.44\,\frac{N}{m}

If we know that k = 444.44\,\frac{N}{m}, x_{o} = 0.41\,m and x_{f} = 0.46\,m, then the work needed is:

W = \frac{1}{2}\cdot \left(444.44\,\frac{N}{m} \right)\cdot (0.46\,m-0.41\,m)^{2}

W = 0.555\,J

0.6 joules of work are needed to stretch the spring from 41 centimeters to 46 centimeters.

b) The elastic force of the ideal spring (F), measured in newtons, is defined by the following formula:

F = k\cdot \Delta x (2)

Where \Delta x is the linear difference from natural length, measured in meters.

If we know that k = 444.44\,\frac{N}{m} and F = 25\,N, then the linear difference is:

\Delta x = \frac{F}{k}

\Delta x = \frac{25\,N}{444.44\,\frac{N}{m} }

\Delta x = 0.056\,m

The spring must be 5.6 centimeters far from its natural length.

3 0
3 years ago
HELPPPPPP (WORTH 20 POINTS)
USPshnik [31]
Answer:
x=2
y=8
Workup in photo below. Good luck.

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The perimeter of a rectangle must be less than 156 feet. If the length is known to be 66 feet, find the range of possible widths
balu736 [363]

x = perimeter

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so, in order to calculate perimeter you need to add two lengths and two widths

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the width has to be less than 12

w < 12

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