Assume that f(5)=8. So, (5, 8) is a point in the graph of f.
For g(x) to give us 8, we need x to be 12, because in that case we would have:
g(12)=f(12-7)=f(5), which is 8. Thus, (12, 8) is a point on the graph of g.
Comparing (5, 8) in f, and (12, 8) in g, we can see that the graph of g is the graph of f shifted 7 units to the right.
Answer: <span>C) The graph of g(x) is the graph of f(x) translated 7 units right.</span>
I think it's a^2 b^2 + 6ab + 9
<span>x+y=30.....(1) and x-y=2......(2) so(1)+(2)......x+y+x-y=30+2 so 2x=32...x=16 now apply x=16 in (1) so we get......16+y=30 so .......y=14</span>
Answer:
the quotient is 6x^2 - 16x + 16, and the remainder is just 4
Step-by-step explanation:
The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}. Division by the binomial x + 1 requires that we use -1 as the divisor. The synthetic division setup becomes:
-1 / 6 -10 0 20
-6 16 -16
-----------------------------
6 -16 16 4
Taking the coefficients {6, -16, 16}, we write the quotient as
6x^2 - 16x + 16, and the remainder as just 4.
Answer:
I'm pretty sure they either terminate after so many digits (end) or repeat a certain pattern of numbers.
Step-by-step explanation:
The first will look like this: 432.2340
The second would look like this: 324.234234234... ("234" would keep repeating over and over and over. And can be any sequence of #'s)
^Random numbers were used as examples^
