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Flura [38]
3 years ago
8

−5 1/5÷(2/3) help plz

Mathematics
1 answer:
navik [9.2K]3 years ago
5 0

Answer:

−5 1/5÷(2/3)≈-7.8

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The rectangles shown below are similar figures. Use the properties of similar figures to solve for the value of s.
Sergeu [11.5K]

Answer:

s = 3

Step-by-step explanation:

we know the rectangles are similar

2 × __ = 16

s × __ = 24

so,

16÷2 = 8

2 × 8 =16

s × 8 =24

then,

24 ÷ 8 = s

3 = s

2 × 8 = 16

3 × 8 =24

hoped i helped :)

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7 x -3 = -21

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Kale can typed 165 words in 3 minutes. How can this ratio be written to show words per minute?
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3 years ago
You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
MatroZZZ [7]

a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

#SPJ1

8 0
2 years ago
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