Question

A car travels in a straight line from a position 50 m to your right to a position 210 m to your right in 5 sec. a. What is the average velocity of the car?b. Construct a position vs. time graph and calculate the slope of the line of best fit.

Answer 1

Answer:

The average velocity of the car is 32 m/s.

Explanation:

Given that,

Initial position = 50 m

Final position = 210 m

Time = 5 sec

(a). We need to calculate the average velocity of the car

Using formula of average velocity

$v_{avg}=\dfrac{v_{f}-v_{i}}{t}$

Put the value into the formula

$v_{avg}=\dfrac{210-50}{5}$

$v_{avg}=32\ m/s$

(b). We need to draw the position vs. time graph

We need to calculate the slope of the line of best fit.

Using formula of slop

$slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Put the value into the formula

$slope =\dfrac{210-50}{5-0}$

$slope =32$

Hence, The average velocity of the car is 32 m/s.