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FinnZ [79.3K]
3 years ago
11

3.

Physics
1 answer:
Svetlanka [38]3 years ago
4 0

Answer:

North and east are at 90 degree, equation becomes

Explanation:

(2x 2)+[2(x+5)] 2=50 2

on solving, we get

x=12.366km/h

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A car traveling at 30 m/s drives off a cliff that is 50 meters high? How far away does it land?
Semenov [28]

Answer:

The maximum range R_{max}= 132. 72 m

Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

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The formula for a projectile that is projected from a height h from the ground is given by the relation

                                R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }  m

Where,

                          g - acceleration due to gravity

Substituting the values in the above equation

                   R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }  

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Hence, the car lands at a distance, R_{max}= 132. 72 m            

3 0
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A climbing rope exerts a force given by F=−kx−cx2. Find an expression for c such that when the rope is stretched a distance d it
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Answer:

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V=\frac{1}{2}kx^2

Now, it is given that at x = d,

V_c=2V

or, \frac{kd^2}{2}+\frac{cd^3}{3}=kd^2

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