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saul85 [17]
3 years ago
6

On his way off to college, Russell drags his suitcase 19 m from the door of his house to the car at a constant speed with a hori

zontal force of 89 N. How much work does Russell do to on the suitcase to overcome friction? Answer to the nearest Joule.
Physics
1 answer:
Mashcka [7]3 years ago
8 0

Answer:

The work done on the suitcase is, W = 1691 J

Explanation:

Given data,

The force on the suitcase is, F  = 89 N

The distance Russell dragged the suitcase, S = 19 m

The work done on the suitcase by Russell is equal to the work done on the suitcase to overcome the friction

The work done on the suitcase by Russell is given by the formula

                          W = F · S

Substituting the given values,

                           W = 89 N x 19 m

                           W = 1691 J

Hence, the work done on the suitcase is, W = 1691 J

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Answer:

1.66 m/s

Explanation:

Work or kinetic energy = \frac{1}{2} mv^{2}

4864=\frac{1}{2} (3540)v^{2}

v = 1.66 m/s

6 0
3 years ago
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I hope this is the correct way to solve

3 0
3 years ago
Anyone know these questions?
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400m in 32sec: (400/32)>12.5meters per second>
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7 0
3 years ago
A formula for the normal systolic blood pressure for a man age a , measured in mmhg, is given as p=0. 006a2−0. 02a 120. Find the
djyliett [7]

The age of a man whose normal blood pressure measures 123 mm of hg

9 years

<h3>What is Quadratic equation ?</h3>

A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = ax^{2} + bx + c, where a, b, and c are numbers and a cannot be 0

P(A) = 0.006 a^{2} - 0.02a + 120

123 = 0.006- 0.02a + 120

0=0.006 a^{2} - 0.02a - 3

you can use the quadratic equation  formula to solve for the man's age.

A = (-b ± (\sqrt{b^{2} - 4*a*c})  ) / (2a)

A = (0.02 ±  \sqrt{(-0.02)^{2} - 4*0.006*(-3)}/ (2*0.006)

A = (0.02 ± \sqrt{0.0076}) / 0.012

A = 9 , -5.67

Age of the man will be 9 years

To learn more about quadratic equation  here

brainly.com/question/17177510?referrer=searchResults

#SPJ4

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2 years ago
How much force is required to accelerate a 22Kg mass at 6 m/s?
GuDViN [60]

Answer:

F = 132N

Explanation:

7 0
3 years ago
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