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Alinara [238K]
3 years ago
5

Which contributes to the lack of evidence of the Period of Heavy Bombardment on Earth? A. Earth's volcanoes B. Earth's magnetic

field C. The moon's gravity D. Earth's atmosphere
Physics
2 answers:
ivann1987 [24]3 years ago
5 0

A. earths volcanoes..

RUDIKE [14]3 years ago
3 0
The correct answer to this would be letter:  

A. Earth’s volcanoes

Together with weathering and plate tectonic movements, Earth’s volcanic eruptions and emission of lava has destroyed/covered many of the craters which were created on Earth during the Period of Heavy Bombardment.

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Atoms that have a positive charge will be attracted to atoms with a
kap26 [50]

Answer:

negative

Explanation:

positive charges attract negative charges and vice versa. and are possible to nullify

4 0
2 years ago
The weights in atwoods machine, starting at rest, attain a velocity of 2ft/sec in one sec. Find the ratio of the masses
Orlov [11]
Refer to the figure shown below.
Let m₁ and m₂ e the two masses.
Let a = the acceleration.
Let T =  tension over the frictionless pulley.

Write the equations of motion.
m₂g - T = m₂a            (1)
T - m₁g = m₁a            (2)

Add equations (1) and (2).
m₂g - T + T - m₁g = (m₁ + m₂)a
(m₂ - m₁)g = (m₁ + m₂)a

Divide through by m₁.
(m₂/m₁ - 1)g = (1 + m₂/m₁)a

Define r = m₂/m₁ as the ratio of the two masses. Then
(r - 1)g = (1 +r)a
r(g-a) = a + g
r = (g - a)/(g + a)

With  = 2 ft/s from rest, the acceleration is
a = 2/32.2 = 0.062 ft/s²
Therefore
r = (32.2 - 0.062)/(32.2 + 0.062) = 0.9962

Answer:
The ratio of masses is 0.9962 (heavier mass divided by the lighter mass).

8 0
3 years ago
A stationary police car emits a sound of frequency 1240 HzHz that bounces off of a car on the highway and returns with a frequen
Tju [1.3M]

Answer

given,

frequency from Police car= 1240 Hz

frequency of sound after return  = 1275 Hz

Calculating the speed of the car = ?

Using Doppler's effect formula

Frequency received by the other car

  f_1 = \dfrac{f_0(u + v)}{u}..........(1)

u is the speed of sound = 340 m/s

v is the speed of the car

Frequency of the police car received

  f_2= \dfrac{f_1(u)}{u-v}

now, inserting the value of equation (1)

  f_2= f_0\dfrac{u+v}{u-v}

  1275=1240\times \dfrac{340+v}{340-v}

  1.02822(340 - v) = 340 + v

   2.02822 v = 340 x 0.028822

   2.02822 v = 9.799

   v = 4.83 m/s

hence, the speed of the car is equal to v = 4.83 m/s

5 0
3 years ago
What are 3 ways an object can be charged
lorasvet [3.4K]
<span>pile
battery
<span>power sector</span></span>
8 0
2 years ago
NEED HELP PLEASE!!!
kenny6666 [7]

Answer:

The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units

Where;

h = The maximum height to which he lifts the barbells

Explanation:

The given parameters are;

The  amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units

The weight of the barbells lifted by the championship lifter, N = 3680 N

The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;

P.E. = m × g × h

Where;

m = The mass of the barbells;

g = The acceleration due to gravity = 9.8 m/s²

h = The maximum height to which the barbells are lifted by the championship weight lifter

m × g = The weight of the barbells = 3680 N

∴ P.E. = 3680 N × h = 3680·h J

By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.

∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units

3 0
2 years ago
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