All categories

2 years ago

How many outer planets are there?

Chemistry

1 answer:

Ivenika [448]2 years ago

3 0

Answer:

four outer planetsThe Outer Planet the four outer planets and the Sun, with sizes to scale. From left to right, the outer planets are Jupiter, Saturn, Uranus, and Neptune. The gas giants are mostly made of hydrogen and helium. These are the same elements that make up most of the Sun.

Explanation:

I hope this helps you

Ari

mwah

You might be interested in

The following properties are either physical or chemical. Which one is different from the rest based on those two category? A.)

Oduvanchick [21]

Answer:

A.)physical B.)physical C.)physical D.)chemical

5 0

3 years ago

Read 2 more answers

IF 500 mL of air contains 2.50x10^22 particles (atoms and molecules). how much particles do you inhale in one day if you breath

vaieri [72.5K]

Answer:

I think it is 0.00192

Explanation:

28.795705

15000

=0.00192

8 0

2 years ago

Give the name (not formula) of the hydrocarbon

nordsb [41]

hydrocarbon is ethene which is used to test for saturation and it undergoes addition reaction

5 0

2 years ago

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0

2 years ago

How many mm are equal to 21 L. How many mg are equal to 9 g. How many grams are equal to 400 kg

liberstina [14]

How many mm are equal to 21 L?

1 L = 1000000 mm

Convert:-

1000000 × 21 = 21000000

21 l = 21000000 mm

How many mg are equal to 9 g?

1 g = 1000 mg

Convert:-

9 × 1000 = 9000

9 g = 9000 mg

8 0

3 years ago