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Nataliya [291]
3 years ago
10

The planet with the greatest temperature extremes is _____.

Physics
2 answers:
ivann1987 [24]3 years ago
6 0

The planet with the greatest temperature extremes is Mercury.

Planets experiences different ranges of the temperature depending on their position with respect to the sun. Since, mercury is the only planet which is too close to the sun, therefore it experiences the high range of the temperature. It experiences 900°F during the day and -350° during the night.

RoseWind [281]3 years ago
4 0
<span><u><em>As you may think that Mercury is he closest planet to the sun,tho its not hotter than Venus.Venus temperature.The surface is </em></u></span><span><u><em>462 °C or 863 °F.</em></u></span>

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If a 15 kg mass accelerates at a rate of 4 m/s2, what net force acts on it?
jarptica [38.1K]
<h2>Answer: D 60N</h2>

<h3>Explanation:</h3>

Mass(M)=15 kg

Acceleration(A)=4 m/s2

Force=?

Now,

Force(F)=M×A

F=15×4

F=60N Ans

5 0
3 years ago
Which of the following is the equation for calculating daily caloric needs? A. BMR calories + Digestion calories B. BMR calories
labwork [276]

Explanation:

To determine your total daily calorie needs, multiply your BMR by the appropriate activity factor, as follows: If you are sedentary (little or no exercise) : Calorie-Calculation = BMR x 1.2. If you are lightly active (light exercise/sports 1-3 days/week) : Calorie-Calculation = BMR x 1.375.

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8 0
3 years ago
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The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o
LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

\bar F \cdot \Delta t = m \cdot  (v_{2}-v_{1}) (1)

Where:

\bar F - Average impact force, in newtons.

\Delta t - Duration of the impact, in seconds.

m - Mass of the sledge hammer, in kilograms.

v_{1}, v_{2} - Initial and final velocity, in meters per second.

If we know that \Delta t = 0.0020\,s, m = 4\,kg, v_{1} = -6\,\frac{m}{s} and v_{2} = 0\,\frac{m}{s}, then we estimate the average impact force is:

\bar F = \frac{m\cdot  (v_{2}-v_{1})}{\Delta t}

\bar F = 12000\,N

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5 0
3 years ago
A basic statement established by experiment or observation.
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3 years ago
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Ilia_Sergeevich [38]

Answer:

7.2 cm

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q = 1.6 x 10^-19 C

The radius of singly changed ion is given by

r = \frac{mv}{Bq}

where, m is the mass of ion, v be the speed of ion, B is the magnetic field and q be the charge

r = \frac{4.39\times 10^{-27}\times 7.92 \times 10^{5}}{0.301\times 1.6\times 10^{-19}}

r = 0.072 m

r = 7.2 cm

5 0
3 years ago
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