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nordsb [41]
4 years ago
6

A car moving along a straight level road has an initial speed of 3 m s-1 and its acceleration is 2 m s-2? What

Physics
2 answers:
BlackZzzverrR [31]4 years ago
7 0

Answer:

13 ms-1

Explanation:

xxMikexx [17]4 years ago
4 0

Answer:

SE RESUELVE CON LA ECUACIÓN DE GALILEO GALILEI

Explanation:

<em>v</em> = 3 m/s + 2 m/s^{2}(5 s) = 13 m/s

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3 years ago
22. What is the length of a pendulum that has a period of 0.500 s?
sergeinik [125]

6.21 cm

  • use the pendulum formula : \sf \bold{\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}}

where

  • T is time or period
  • π is pie = 22/7
  • L is pendulum length
  • g is acceleration due to gravity

Given:

  • T = 0.500 s
  • g = 9.8 m/s²

solving step-wise:

\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}

\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}

\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}

\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }

\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2

\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8

\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m

  • 1 m → 100 cm

\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm

\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm             { rounded to nearest hundredth }

6 0
2 years ago
Read 2 more answers
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