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pickupchik [31]
3 years ago
12

what is the approximate weight of a 20-kg cannonball on the moon if the acceleration due to gravity is 1.6m/s^2

Physics
1 answer:
monitta3 years ago
5 0
On Earth, a cannonball with a mass of 20 kg would weigh 196 Newtons.
With the formula F=mg, where F is the weight in Newtons, m is the mass, and g is the acceleration due to gravity on the Earth which is 9.8m/s^2.
F=20kg x 9.8m/s^2= 196 Newtons

BUT on the moon, acceleration due to gravity is 1.6 m/s^2,
so F=mg=20kgx1.6m/s^2= 32 N
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a block has a volume of 0.09m3 and a density of 4,000kg/m3. what's the force of gravity acting on the block in water
Lunna [17]
       Density = (mass) / (volume)

                                4,000 kg/m³ = (mass) / (0.09 m³)

Multiply each side
by  0.09 m³ :           (4,000 kg/m³) x (0.09 m³) = mass

                                 mass = 360 kg .

Force of gravity = (mass) x (acceleration of gravity)

                           = (360 kg) x (9.8 m/s²)

                           = (360 x 9.8)  kg-m/s²

                           =   3,528 newtons .  

That's the force of gravity on this block, and it doesn't matter 
what else is around it.  It could be in a box on the shelf or at 
the bottom of a swimming pool . . . it's weight is 3,528 newtons 
(about 793.7 pounds). 

Now, it won't seem that heavy when it's in the water, because 
there's another force acting on it in the upward direction, against 
gravity.  That's the buoyant force due to the displaced water.

The block is displacing 0.09 m³ of water.  Water has 1,000 kg of 
mass in a m³, so the block displaces 90 kg of water.  The weight 
of that water is  (90) x (9.8) = 882 newtons (about 198.4 pounds), 
and that force tries to hold the block up, against gravity.

So while it's in the water, the block seems to weigh

       (3,528  -  882) = 2,646 newtons  (about 595.2 pounds) . 

But again ... it's not correct to call that the "force of gravity acting 
on the block in water".  The force of gravity doesn't change, but 
there's another force, working against gravity, in the water.
5 0
3 years ago
A person walks in the following pattern: 3.1 km north, then 2.4 km west, and finally 5.2 km south. a) Sketch the vector diagram
zysi [14]

Answer:

d = 3.19 km

direction is given as

\theta = 41.2 degree South of West

Explanation:

Part b)

displacement is given as

d_1 = 3.1 \hat j

d_2 = 2.4 \hat i

d_3 = 5.2(-\hat j)

now we will have

d = d_1 + d_2 + d_3

d = 2.4 \hat i + (3.1 - 5.2)\hat j

d = 2.4 \hat i - 2.1 \hat j

total displacement is given as

d = \sqrt{2.4^2 + 2.1^2}

d = 3.19 km

direction is given as

tan\theta = \frac{-2.1}{2.4}

\theta = 41.2 degree South of West

3 0
4 years ago
A negative velocity, approaching zero, represents a negative acceleration. True or False
ruslelena [56]

Answer:

False.

Explanation:

Lets assume our positive direction to the right (this reasoning works for any direction). A negative velocity would then be then directed to the left. If it varies as such that it aproaches to zero, it means that the variation is directed to the right, and that is where the direction of the acceleration must be pointing. In other words, its losing its velocity, so the acceleration must point opposite to the velocity. Then it means the acceleration is positive.

8 0
4 years ago
If a net force of 800n is acting on an object with a mass of 60kg. What would be the objects accelerations
aivan3 [116]

Answer: 13.33 m/s^2

Explanation:

Force is the product of mass of an object and its acceleration.

i.e Force = Mass x Acceleration

Since Force on object = 800N

Mass of object = 6Kg

Acceleration = ?

Then, Force = Mass x Acceleration

800N = 60Kg x Acceleration

Acceleration = (800N/60kg)

Acceleration = 13.33 m/s^2 (The unit of acceleration is metre per second square)

Thus, the objects accelerations is 13.33 m/s^2

5 0
4 years ago
An image cannot be projected and forms where light rays appear to originate.
irakobra [83]

An VIRTUAL image cannot be projected, and

forms where light rays appear to originate.

3 0
3 years ago
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