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pickupchik [31]
3 years ago
12

what is the approximate weight of a 20-kg cannonball on the moon if the acceleration due to gravity is 1.6m/s^2

Physics
1 answer:
monitta3 years ago
5 0
On Earth, a cannonball with a mass of 20 kg would weigh 196 Newtons.
With the formula F=mg, where F is the weight in Newtons, m is the mass, and g is the acceleration due to gravity on the Earth which is 9.8m/s^2.
F=20kg x 9.8m/s^2= 196 Newtons

BUT on the moon, acceleration due to gravity is 1.6 m/s^2,
so F=mg=20kgx1.6m/s^2= 32 N
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Name two things that the people standing on the street corner would say are in motion
timurjin [86]
People, and cars
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8 0
3 years ago
A boy throws a ball with an initial velocity of 19.6 m/s. What maximum height does the ball reach?
Wewaii [24]
<h2>Hello!</h2>

The answer is: 19.59 m

<h2>Why?</h2>

Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.

When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:

We will use the following formula:

Vf^2=Vi^2+2*g*s

Where:

Vf= Final velocity = 0

Vi= Initial velocity = \frac{19.6m}{s}

g = Gravity Acceleration = \frac{9.81m}{s^{2} }

s = Traveled distance

0=19.6^2+2*-9.81*s\\s=\frac{19.6^2}{2*9.81}=\frac{384.16}{19.62}=19.59m

Have a nice day!

8 0
3 years ago
Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the
saul85 [17]

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

R=\alpha \frac{l}{s}

Were:

R is resistance

\alpha is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area (s=\pi r^{2}).

So if the lenght and radius are doubled, the equation goes as follows:

R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }

So finally because the circular area is a square function, the resulting equation is half of the one before.

7 0
3 years ago
A circuit consists of an ideal ac generator, a capacitor, and an ideal inductor, all connected in series. The charge on the capa
Serjik [45]

Answer:

-16\omega sin(\omega t + \pi/4)

Explanation:

The function of the current with respect to time is the derivative of the charge function with respect to time t. We can apply chain rule to differentiate it:

I(t) = Q'(t) = (16cos(\omega t + \pi/4))' \\= -16(\omega t + \pi/4)' sin(\omega t + \pi/4) \\= -16\omega sin(\omega t + \pi/4)

7 0
3 years ago
Read 2 more answers
What is the primary difference between an ideal emf device and a real emf device?.
EleoNora [17]

Answer:

A real emf device has an internal resistance, but an ideal emf device does not.

3 0
2 years ago
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