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k0ka [10]
2 years ago
7

As one moves farther and farther from the Sun, the distance between adjacent planets is _____.

Physics
1 answer:
Alenkinab [10]2 years ago
4 0
As one moves farther and farther from the Sun, the distance between adjacent planets is greater.
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A ball is thrown straight up from a point 2 m above the ground. The ball reaches a maximum height of 3 m above its starting poin
qwelly [4]

Answer:

2 m

Explanation:

The displacement of any body is the shortest distance in an object's path between its initial and final point.

The ball would travel 3 m from the point of throwing then fall down 5 m to the ground. The total distance traveled is 7 m.

The displacement of the ball will be the distance from the point of throwing to the ground i.e., 2 m as it is the shortest distance between the initial and final point of the ball's journey.

8 0
3 years ago
Question from my vector statics class (deals with vectors from physics)
jeka57 [31]
Haven't done one like this in awhile but I see no one is answering so I gave it a try.  I think it's right but let me know if you see something fishy...

4 0
2 years ago
Read 2 more answers
What might cause a theory to change over time?
Olin [163]

Answer:

A theory does not change into a scientific law with the accumulation of new or better evidence. A theory will always remain a theory

Explanation:

theories and laws could potentially be falsified by countervailing evidence. Theories and laws are also distinct from hypotheses.

5 0
3 years ago
Alan starts from his home and walks 1.3 km east to the library. He walks an additional 0.68 km east to a music store. From there
zepelin [54]

Answer: final Displacement = 0 km, total distance covered =7 km

Explanation:

Given the following :

From home to library = 1.3 km East

Library to music store = 0.68km East

Music store to friend's house = 1.1km North

Friend's house to grocery store = 0.42 km North

Displacement is the net change in distance traveled.

Eastward distance :

To = (1.3 + 0.68)km = 1.98km East

Fro = (0.68 + 1.3)km = 1.98 km East

Δ distance = (1.98 - 1.98) = 0

Northward direction:

To = (1.1 + 0.42)km = 1.52km north

Fro = (0.42 + 1.1)km = 1.52km North

Δ distance = (1.98 - 1.98) = 0

Hence final Displacement = 0

Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5

= 7km

3 0
3 years ago
Energy Conservation With Conservative Forces: If a spring-operated gun can shoot a pellet to a maximum height of 100 m on Earth,
crimeas [40]

Answer:

h' = 603.08 m

Explanation:

First, we will calculate the initial velocity of the pellet on the surface of Earth by using third equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity on the surface of earth = - 9.8 m/s² (negative sign due to upward motion)

h = height of pellet = 100 m

Vf = final velocity of pellet = 0 m/s (since, pellet will momentarily stop at highest point)

Vi = Initial Velocity of Pellet = ?

Therefore,

(2)(-9.8 m/s²)(100 m) = (0 m/s)² - Vi²

Vi = √(1960 m²/s²)

Vi = 44.27 m/s

Now, we use this equation at the surface of moon with same initial velocity:

2g'h' = Vf² - Vi²

where,

g' = acceleration due to gravity on the surface of moon = 1.625 m/s²

h' = maximum height gained by pellet on moon = ?

Therefore,

2(1.625 m/s²)h' = (44.27 m/s)² - (0 m/s)²

h' = (1960 m²/s²)/(3.25 m/s²)

<u>h' = 603.08 m</u>

4 0
2 years ago
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