In the experiment of free fall bob released a bag of mass 1 lb
so here we can say that initial speed of the bag is Zero
time taken by the bag to free fall is given as
t = 1.5 s
also the acceleration of free fall is given as
a = 9.8 m/s^2
now we will use kinematics equation here for finding the distance of free fall




so the bag will fall down by total distance of 11.025 m from its initial released position.
I believe there should be some sort of table attached. Unfortunately I cannot answer this question. Sorry!
It’s FF= μ•Fn
Ff stands for friction force
The weird symbol is your coefficient of friction which has no units
Fn stands for normal force
Answer:
6.62607004 x 10^(-34)m²kg/s
Explanation:
This is the constant that shows the value of energy of a photon in relation to it's frequency.
Please let me know if you want this explained further!
Thanks!
<span>A- 2*[(m1 - m2)/(m1 + m2)]*g/L
The rotation is in the counterclockwise direction and the angular acceleration is positive.
B- 2*[(m1 - m2)/(m1+ m2 +mbar/3)]*g/L
The rotation is in the counterclockwise direction and the angular acceleration is positive.</span>