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slega [8]
2 years ago
11

For f(x) = 2x +1 and g(x) = x^2-7, find (f/g) (x)

Mathematics
1 answer:
Rashid [163]2 years ago
5 0
the answer is (f/g)(x) = 2(x^2 - 7) + 1
= 2x^2 - 14 + 1
= 2x^2 - 13
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A group of 24 students have recess together. They are making teams to play a game. Each team has to have exactly 5 players, and
solmaris [256]

Answer:

They can make 4 teams.

Step-by-step explanation:

You can see that 24 cannot be divided by 5, but you can subtract 4 from 24 to get 20, which is a multiple of 5. 20 divided by 5 is 4, so they can make 4 teams.

8 0
2 years ago
If the discriminant, b^2-4ac is ___, a quadratic will have two real roots, two points of intersection with the x-axis.
den301095 [7]

If the discriminant, b² - 4ac is<u> positive</u>

<h3>How to complete the statement?</h3>

From the question, we have the following equation of discriminant

The discriminant (d) is calculated as

d = b² - 4ac

The solutions of a quadratic equation are dependent on the following conditions

  • If d = 0, the quadratic equation has 1 real solution
  • If d < 0, the quadratic equation has imaginary solutions
  • If d > 0, the quadratic equation has 2 different real solutions

This means that "d > 0, the quadratic equation has 2 different real solutions" implies that the discriminant is positive

Hence, the complete statement is (b) positive

Read more about discriminant at

brainly.com/question/64103

#SPJ1

6 0
11 months ago
F(x)=4x-8 and g(x)=5x+6, find (f+g)(x)
ASHA 777 [7]

Answer:

9x-2

Step-by-step explanation:

Since you are adding the two functions, you should first start adding like terms. 4x + 5x is 9x. -8 + 6 is -2. Thus the value of (f+g)(x) is 9x-2.

3 0
3 years ago
Brooke had 70 chairs but he had less than20 rows how many chair he can put on each row
RideAnS [48]
Put in a equality

20 > (70/x)

then you solve 

20x > 70

x>70/20

x> 3.5    you can not put part of a chair in a row so you round up

****You can put  4 or more chairs in a row****



4 0
2 years ago
Read 2 more answers
Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y
Charra [1.4K]

I assume you mean y_1=t^{-1}, and not y_1=t-1, since this doesn't satisfy the ODE.

Assume a second solution of the form y_2=vy_1, where v is a function of t. Then

{y_2}'=v'y_1+v{y_1}'

{y_2}''=v''y_1+2v'{y_1}'+v{y_1}''

Substituting into the ODE gives

t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0

\implies tv''+v'=0

\implies(tv')'=0

\implies tv'=C

\implies v'=\dfrac Ct

\implies v=C_1\ln|t|+C_2

\implies y_2=\dfrac{\ln t}t

where we omit the second term because it's already accounted for by y_1.

3 0
3 years ago
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