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BaLLatris [955]
3 years ago
7

Determine if the expression is a polynomial or not. If it is a polynomial, state the

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

Step-by-step explanation:

yes that

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Find the standard equation of a parabola with a vertex of (-3,1)
kkurt [141]
1. Parabola's equation is y = a(x + b)^2 + c, where (b, c) is the vertex.
2. We have y = a(x - 3)^2 + 1
3. Take everything to the left side:
-a(x - 3)^2 + y - 1 = 0
That's the standard equation. Hope this helps! :)
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3 years ago
5r^2-13r-6=0 <br><br> How do I solve this
frosja888 [35]

5 {r}^{2}  - 13r - 6 = 0 \\ a = 5 \\ b =   - 13 \\ c =  - 16 \\

<em>r</em><em>=</em><em> </em><em><u>-</u></em><em><u>(</u></em><em><u>-</u></em><em><u>1</u></em><em><u>3</u></em><em><u>)</u></em><em><u>±</u></em><em><u>></u></em>

<em><u>\sqrt{( - 13) {}^{2} }  - 4.5( - 6)</u></em>

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<em>r</em><em>=</em><em> </em><em><u>1</u></em><em><u>3</u></em><em><u>±</u></em><em><u>1</u></em><em><u>7</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em>

<em>r</em><em>=</em><em><u>1</u></em><em><u>3</u></em><em><u>+</u></em><em><u>1</u></em><em><u>7</u></em>

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<em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em>

<em>r = 2 \\ r =  \frac{ - 2}{5}</em>

<em>this \: the \: answer \: your \: question \\  \\ mark \: me \: as \: a \: brainlist \: plz</em>

7 0
3 years ago
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Evaluate the expression when x = 3 and y = 5 6y/x
kondaur [170]
If x=3 and y=5 then you just substitute.
6(5)/3
30/3
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10 is your answer.
5 0
3 years ago
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Simplify: 3m/m-6*5m^3-30m^2/5m^2<br>A.7<br>B.m+7<br>C.m+8<br>D.3m
VLD [36.1K]
<span>I think you meant this: (3m/m-6)*(5m^3-30m^2/5m^2)
If that's the case, the simplified form:
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garri49 [273]
I believe the answer is 7x-y
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