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3 years ago

30 is greater than 29 draw quick pictures to explain

Mathematics

2 answers:

xenn [34]3 years ago

3 0

Answer: yes

Step-by-step explanation: 30 is one more then 29

7nadin3 [17]3 years ago

3 0

Lemme tell ya these questions are dumb

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Find the future value of $2000 invested at annual rate of 2.4% compounded quarterly for 8 years. Round your answer to hundredths

MatroZZZ [7]

Answer: $2421.95

Step-by-step explanation:

A = p(1 + r/n) ^nt

A= 2000(1+0.024/4)^4x8

A= 2421.95

3 0

3 years ago

Can someone help me with (d)

zysi [14]

Answer:

Step-by-step explanation:

1 to the power of anything is still one

1 * 1 * 1 * 1 = 1

8 0

2 years ago

Which of the following is equivalent to (5) 3 O 54 O 54 05 O V5

IrinaK [193]

Answer:

D. $\sqrt[3]{5^7}$

Step-by-step explanation:

The formula for this conversion is:

$a^\frac{x}{n}=\sqrt[n]{a^x}$

Substitute the values you currently have.

$5^\frac{7}{3}=\sqrt[n]{a^x}$

Since we know that

a = 5

x = 7

n = 3

Fill the square root with this.

$5^\frac{7}{3}=\sqrt[3]{5^7}$

4 0

2 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

2 years ago

Complete the statement:

r-ruslan [8.4K]

Angle 12 and Angle 10 are vertical angles.

7 0

2 years ago