1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikdorinn [45]
2 years ago
5

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

lowing data have been gathered. Downtown Store North Mall Store Sample size 25 20 Sample mean $9 $8 Sample standard deviation $2 $1 A 95% interval estimate for the difference between the two population means is a. .071 to 1.929. b. 1.09 to 4.078. c. 1.078 to 2.922. d. .226 to 1.774.
Mathematics
1 answer:
Julli [10]2 years ago
4 0

Answer:

0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

You might be interested in
Please helppppppppppppppppp
Alex777 [14]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
An arithmetic sequence has t1 = 6 and common difference 2 find t12 and s12​
Sergeeva-Olga [200]

Answer:

See below ~

Step-by-step explanation:

Finding t₁₂ :

⇒ t₁₂ = t₁ + 11d

⇒ t₁₂ = 6 + 11(2)

⇒ t₁₂ = 6 + 22

⇒ t₁₂ = 28

=============================================================

Finding S₁₂ :

⇒ S₁₂ = 12/2 × 2t₁ + (12 - 1)d

⇒ S₁₂ = 6 × 2(6) + 11(2)

⇒ S₁₂ = 6 × 12 + 22

⇒ S₁₂ = 6 × 34

⇒ S₁₂ = 204

4 0
1 year ago
A recent study found that the average length of caterpillars was 2.8 centimeters with a
pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 2.8, \sigma = 0.7.

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 2.8}{0.7}

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0
2 years ago
suppose a triangle has two sides of length 32 and 35, and that the angle between these two sides is 120. what is the length of t
Vesnalui [34]
Using cosine rule, the length of the required side = sqrt(32^2 + 35^2 - 2 x 32 x 35cos 120)
= sqrt(1024 + 1225 - (-1120))
= sqrt(2249 + 1120)
= sqrt(3369)
= 58.04
4 0
3 years ago
Answer A , B , C or D. Need some help!
creativ13 [48]

Answer:

c

Step-by-step explanation:

system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. The solution of such a system is the ordered pair that is a solution to both equations. ... The solution to the system will be in the point where the two lines intersect.

3 0
3 years ago
Other questions:
  • Ally's hair grew from 10 10 \frac{3}{4} 4 3 ​ inches to 13 13 \frac{1}{4} 4 1 ​ inches over 5 months. At what rate did Ally's ha
    6·1 answer
  • Which is the best estimate of watch percent?
    8·1 answer
  • Which statement correctly compares the weight of a newborn beluga and newborn muskox
    13·1 answer
  • Help me out quickly plz
    13·1 answer
  • What is the equation of the line shown below?
    5·1 answer
  • Rob is setting up a model train track that is 3 3/8 feet long no telephone pole is needed at the start of the track. However alo
    8·1 answer
  • -5x + 4(2x + 1)<br> please help!<br> (simplify it)
    7·2 answers
  • Please help
    11·1 answer
  • Math experts!! Please factor this completely thank you
    8·1 answer
  • Let f(x) = x^3-3x^2+2 and g(x) = x^2 -6x+11 Enter the value of x such that f(x)=g(x)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!