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Mars2501 [29]
4 years ago
6

Multiple-choice questions have a special grading rule determined by your instructor. Assume that your instructor has decided to

grade these questions in the following way: If you submit an incorrect answer to a multiple-choice question with n options, you will lose 1/(n−1) of the credit for that question. Just like the similar multiple-choice penalty on most standardized tests, this rule is necessary to prevent random guessing.If a multiple-choice question has five answer choices and you submit one wrong answer before getting the question correct, how much credit will you lose for that part of the question?
Mathematics
2 answers:
Daniel [21]4 years ago
6 0

Answer:

  1/4 of the credit

Step-by-step explanation:

The problem statement tells you n=5. Putting that into the expression for lost credit, you get ...

  1/(5-1) = 1/4

of the credit is lost for a question with 1 wrong answer.

You will lose 1/4 of the credit.

Reika [66]4 years ago
5 0

Answer:

The credit will you lose for the part of question is 1/4 or 25%.

Step-by-step explanation:

Consider the provided information.

It is given that, if you submit an incorrect answer to a multiple-choice question with n options, you will lose 1/(n−1) of the credit for that question.

Suppose the given multiple choice question has 5 answer. So for one wrong answer the loss will be:

Substitute the value of n=5 in above formula.

\frac{1}{n-1} \\\frac{1}{5-1} \\\frac{1}{4}=0.25

That means you will lose 1/4 or 0.25credit.

Now convert it into %.

\frac{1}{4}\times 100=25\%

Hence, the credit will you lose for the part of question is 1/4 or 25%.

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2 years ago
A farmer is building a fence to enclose a rectangular area consisting of two separate regions. The four walls and one additional
Vlad [161]

Answer:

The maximal area will be "1093.5 square feet".

Step-by-step explanation:

Let,

Length = L feet

Breadth = b feet

Given Total fencing = 162 feet

According to the question,

 (2\times L)+(3\times b)=162

              2L+3B=162

                         L=\frac{162-3b}{2}

                         L=81-\frac{3}{2}b

As we know,

 Area=Length\times breadth

          =(81-\frac{3}{2}b)\times b

          =81b-\frac{3}{2}b^2

Now, we required to decrease or minimize the are. So for extreme points:

 \frac{dA}{db}=0

or,

 \frac{dA}{dB}=\frac{d}{db}(81-\frac{3}{2}b^2 )=0

       81-\frac{3}{2}\times 2\times b=0

                            b=\frac{81}{3}

                            b=27 \ feet

Now on putting the value of b, we get

 l=81-\frac{3}{2}\times 27

   =81-40.5

   =40.5 \ feet\\

So that the dimensions will be:

⇒  40.5 feet by 27 feet

Therefore when the dimension are above then the area will be:

=  81\times 27-\frac{3}{2}\times 27\times 27

=  2187-\frac{3}{2}\times 729

=  2187-1093.5

=  1093.5 \ square \ feet

6 0
3 years ago
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