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Mars2501 [29]
4 years ago
6

Multiple-choice questions have a special grading rule determined by your instructor. Assume that your instructor has decided to

grade these questions in the following way: If you submit an incorrect answer to a multiple-choice question with n options, you will lose 1/(n−1) of the credit for that question. Just like the similar multiple-choice penalty on most standardized tests, this rule is necessary to prevent random guessing.If a multiple-choice question has five answer choices and you submit one wrong answer before getting the question correct, how much credit will you lose for that part of the question?
Mathematics
2 answers:
Daniel [21]4 years ago
6 0

Answer:

  1/4 of the credit

Step-by-step explanation:

The problem statement tells you n=5. Putting that into the expression for lost credit, you get ...

  1/(5-1) = 1/4

of the credit is lost for a question with 1 wrong answer.

You will lose 1/4 of the credit.

Reika [66]4 years ago
5 0

Answer:

The credit will you lose for the part of question is 1/4 or 25%.

Step-by-step explanation:

Consider the provided information.

It is given that, if you submit an incorrect answer to a multiple-choice question with n options, you will lose 1/(n−1) of the credit for that question.

Suppose the given multiple choice question has 5 answer. So for one wrong answer the loss will be:

Substitute the value of n=5 in above formula.

\frac{1}{n-1} \\\frac{1}{5-1} \\\frac{1}{4}=0.25

That means you will lose 1/4 or 0.25credit.

Now convert it into %.

\frac{1}{4}\times 100=25\%

Hence, the credit will you lose for the part of question is 1/4 or 25%.

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A simple random sample of size equals 49 is obtained from a population with mu equals 88 and sigma equals 14. ​(a) Describe the
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Answer:

a) \bar X \sim N(88,\frac{14}{\sqrt{49}}=2)  

b) P(\bar X >91.2)=1-P(\bar X

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

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The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

Let X the random variable that represent the variable of interest on this case, and for this case we know the distribution for X is given by:  

X \sim N(\mu=88,\sigma=14)  

And let \bar X represent the sample mean, by the central limit theorem, the distribution for the sample mean is given by:  

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})  

​(a) Describe the sampling distribution of x overbar.

\bar X \sim N(88,\frac{14}{\sqrt{49}}=2)  

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First we can to find the z score for the value of 91.2. And in order to do this we need to apply the formula for the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

If we apply this formula to our probability we got this:  

z=\frac{91.2-88}{\frac{14}{\sqrt{49}}}=1.6

And we want to find this probability:

P(\bar X >91.2)=1-P(\bar X

On this last step we use the complement rule.

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