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3 years ago

Can someone please help me on this?

Mathematics

1 answer:

Darya [45]3 years ago

3 0

I think 5 and 2 are linear pairs, 3 and 4 are complementary angles, 1 and 2 are vertical angles, and 5 and 2 are also supplementary angles
I could be wrong but I’m pretty sure!!

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I REALLY NEED HELP ASAP<3 :)If the answer is not a whole number, it should be entered as a decimal rounded to the hundredths

Degger [83]

If her hourly rate stays the same, how many hours would she have to work to earn $217 next week? ... She wants to enlarge the photograph so that its width is 10 in. ... Cross-Multiply: (4)(x)=(6)(10); Simplify: 4x=60; Divide both sides by 4 to find the height of the new photograph: \frac{4x}{4}=\frac{60}{4. Answer: 15 inches .

8 0

3 years ago

There are 12 inches in 1 foot. Jada is working on improving her vertical jump. She records,

guajiro [1.7K]

Answer:

There are 72 inches in 6 feet.

Step-by-step explanation:

Given:

There are 12 inches in 1 foot.

Jada is working on improving her vertical jump.

Currently, her standing reach is 6 feet from the ground.

Now, to find the inches in 6 feet.

Let the inches in 6 feet be $x.$

As given:

In 1 foot there are 12 inches.

So, 1 foot is equivalent to 12 inches.

Thus, 6 feet is equivalent to $x$

Now, to find using cross multiplication method:

$\frac{1}{12} =\frac{6}{x}$

By cross multiplying we get:

$x=72$

So, the inches in 6 feet = 72.

Therefore, there are 72 inches in 6 feet.

3 0

3 years ago

Find the measure of angle N. A. 150° B. 8° C . 90° D. 294°

oee [108]

Answer:

$\angle N=150\degree$

Step-by-step explanation:

The sum of interior angles of a 5-sided polygon is 540 degrees.

We sum all the angles to get:

<M+<L+<N+<O+<P=540

90+90+(17x+4)+(18x+6)+(10x-10)=540

45x+180=540

45x=540-180

45x=360

x=8

N=18*8+6

$\angle N=150\degree$

8 0

3 years ago

Find the unknown dimension of a rectangle if its area is 216 square miles and one dimension measures 6 miles. Use labeled sketch

Sedaia [141]

12 but it depends on your time

3 0

2 years ago

Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists

7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20

6 0

3 years ago