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Oksana_A [137]
2 years ago
11

Write each decimal as a percent. 1. 0.74

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
5 0

Answer:

1. 0.74 = 74%

4. 0.617 = 61.7

6. 68% = 0.68

9. 175% = 1.75

2. 0.15 = 15%

5. 0.834 = 83.4%

7. 34% = 0.34

10. 200% = 2.00

3. 0.09 = 9%

8. 58.5% = 0.585

Step-by-step explanation:

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At a competition with 8 runners, 2 medals are awarded for first and second
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Answer: Option 'A' is correct.

Step-by-step explanation :

Since we have given that

Number of medals = 2

Number of runners = 8

We need to find the number of ways to award the medals.

We would use "fundamental theorem of counting" to find the number of ways.

So, number of ways is given by

8 × 7 = 56

Hence, option 'A' is correct.

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3 years ago
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Solve for j: j + j / 2 + J + 5 = 45
Georgia [21]

Answer:

j:5j/2+5=45 Or j=16 how you put it was a little confusing

5 0
2 years ago
PLEASE HELP!!!!!!!!!!!!! DUE SOON
Sergio039 [100]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t


now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)


\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)

6 0
2 years ago
Y'=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B-2x%2B2y%2B1%7D%7Bx-y%2B1%7D" id="TexFormula1" title="\frac{-2x+2y+1}{x-y+1}" alt
AlladinOne [14]

Answer:

see below

Step-by-step explanation:

 dx        2+2xy         1                1                  2               2

____ =   ______ – ___x^2 – ____y^2 – _____x + ______y

 dy            3            3                3                 3                3

8 0
2 years ago
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