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Alborosie
3 years ago
6

What is the percentage of sugar in the syrup made of 10 kg of water and 15 kg of sugar?

Mathematics
2 answers:
ra1l [238]3 years ago
4 0

Step-by-step explanation:

divide the weight of the sugar by the weight of the water then multiply it by hundred

SCORPION-xisa [38]3 years ago
4 0

Answer:

60%

Step-by-step explanation:

15/(15+10) × 100

15/25 × 100 = 60%

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last month leonardo went to the gas station 5 times to buy gas for his car the numbers of gallons he purchased were 14.071, 14.3
zavuch27 [327]

Answer:

its 14.32

Step-by-step explanation:

because if you line all the numbers up and you look in the hundreds place 3 is the biggest number

8 0
3 years ago
three cones have a volume of 192π cm³.Cone A has a radius of 2 cm. Cone B has a radius of 3 cm. Cone C has a radius of 4 cm. fin
andrew11 [14]

9514 1404 393

Answer:

  A: 144 cm

  B: 64 cm

  C: 36 cm

Step-by-step explanation:

The volume of a cone is given by ...

  V = (1/3)πr²h

Solving for h, we get ...

  3V/(πr²) = h

Filling in the given values, we get ...

  3(192π)/(πr²) = h

  576/r² = h

Then the heights of the different cones are ...

  A: r = 2, h = 576/4 = 144 . . . cm

  B: r = 3, h = 576/9 = 64 . . . cm

  C: r = 4, h = 576/16 = 36 . . . cm

8 0
3 years ago
A hockey season ticket holder pays $99.00 for her tickets plus $3.00 for a program for each game. A second person pays $14.00 fo
ddd [48]

The two person will pay the same amount of money when they both watch 9 hockey games.

<h3>How to find the equation and use it to find cost?</h3>

A hockey season ticket holder pays $99.00 for her tickets plus $3.00 for a program for each game. Therefore,

y = 99 + 3x

where

y = total cost

x = number of game

A second person pays $14.00 for a ticket to every game but doesn't buy programs. Therefore,

y = 14x

The number of games they will have the same amount is as follows:

99 + 3x = 14x

99  = 14x - 3x

99 = 11x

x = 99 / 11

x = 9

Therefore, they will have the same amount when they watch 9 games.

learn more on equation here: brainly.com/question/14058936

4 0
2 years ago
You have 12 coins, one of which is fake. The fake coin is indistinguishable from the rest except that it is heavier. Can you det
Anton [14]
Yep! 
Weighing #1: Start off by splitting the pile of 12 coins evenly into two piles, 6 in each pile. Put one pile on each side of the balance. The side that is weighed down has the fake coin it in. Ignore the other 6 coins.

Weighing #2: Now you have 6 coins left. Split the pile evenly again, 3 in each pile. Repeat the same process and put each pile on one side of the balance. The side that is weighed down has your fake coin in it. Ignore the other 3 coins.

Weighing #3: You have 3 coins left. Take two coins, whichever two you like, and weigh them. If they weigh the same, then the one you didn't weigh is the fake one. If one is heavier, then that heavier one is your fake coin.
5 0
3 years ago
Read 2 more answers
100x100x100 i don't know this
kotykmax [81]

Answer:

1000000

Step-by-step explanation:

4 0
2 years ago
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