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Verdich [7]
2 years ago
10

Please help and explain how you got the answer I'm really bad at these

Mathematics
2 answers:
irina1246 [14]2 years ago
6 0
The range of the data is C. 160 because the biggest number, 280, subtracted by the smallest number, 120, is equal to 160.
swat322 years ago
6 0
Here, Median of Q1 = 140+150/2 = 290/2 = 145
Median of Q3 = 226+245/2 = 471/2 = 235.5

Now, Interquartile range = 235.5 - 145 = 90.5

In short, Your Answer would be Option B

Hope this helps!
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Write the ratio 4 L : 5.6 L as a fraction in the simplest form with whole numbers in the numerator and denominator
Fiesta28 [93]

Answer:

Step-by-step explanation:

It's 5/7

You get that by having a calculator that does that. If you don't then the way to do it is multiply the numerator and denominator by 1.25

4 * 1.25 = 5

5.6 * 1.25 = 7

8 0
2 years ago
What is the answer for <br> 15 + b =23
riadik2000 [5.3K]
15 plus 8 equals 23.
4 0
2 years ago
Read 2 more answers
Isabella averages 152 points per bowling game with a standard deviation of 14.5 points. Suppose Isabella's points per bowling ga
Serga [27]

Answer:

The z-score when x=187 is 2.41. The mean is 187. This z-score tells you that x = 187 is 2.41 standard deviations above the mean.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 152, \sigma = 14.5

The z-score when x=187 is ...

Z = \frac{X - \mu}{\sigma}

Z = \frac{187 - 152}{14.5}

Z = 2.41

The z-score when x=187 is 2.41. The mean is 187. This z-score tells you that x = 187 is 2.41 standard deviations above the mean.

3 0
2 years ago
Select the pair of slopes that are the slopes of perpendicular lines.
agasfer [191]
<h3>\frac{3}{4}\ and\ \frac{-4}{3} are the slopes of perpendicular lines</h3>

<em><u>Solution:</u></em>

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

<em><u>Option 1</u></em>

\frac{1}{2}\ and\ 2

Product = \frac{1}{2} \times 2 = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 2</u></em>

\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1

This option satisfies the slopes of perpendicular lines

<em><u>Option 3</u></em>

\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 4</u></em>

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0
3 years ago
A rain storm came through Clifton park and it was accumulating 2/3 inches of rain/hour. How many inches of rain would fall in 6
nlexa [21]

4 inches of rain would fall in 6 hours

<h3><u>Solution:</u></h3>

Given that, A rain storm came through Clifton park  

And it was accumulating \frac{2}{3} inches of rain/hour

So amount of rain accumulated in 1 hour = \frac{2}{3}

Thus amount of rain accumulated in six hours is calculated by multiplying the amount of water accumulating per hour and 6

Amount of water accumulated in 6 hours = Amount of water accumulated in 1 hour \times 6

\text { Amount of water accumaulated in 6 hours }=\frac{2}{3} \times 6=4

<em><u>Another way:</u></em>

Let "n" be the amount of rain accumulated in 6 hours

1 hour ⇒ \frac{2}{3} rain accumulated

6 hours ⇒ "n"

By cross multiplication, we get

6 \times \frac{2}{3} = 1 \times n\\\\n = \frac{2}{3} \times 6 = 4

Hence, 4 inches of rain would fall in 6 hours.

4 0
3 years ago
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