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Nutka1998 [239]
3 years ago
15

A classroom has a length of 30 ft. and a width of 20 ft. The flooring is to be replaced by tiles. If each tile has a length of 3

6 in. and a width of 24 in., how many tiles are needed to cover the classroom floor?
Mathematics
1 answer:
Mashcka [7]3 years ago
3 0

Answer:

100

Step-by-step explanation:

Hello! to calculate the number of tiles needed for the floor you need two things

1. number of tiles that fit across the width, this is achieved by dividing the total width by the width of each tile

Width=20ft=240in

N1=\frac{240}{24} =10

2.number of tiles that fit in the logitude, this is achieved by dividing the total length by the length of each tile.

leght=30ft=360in

N2=\frac{360}{36} =10

Finally, you multiply the number of tiles that fit in width by the number of tiles that fit in length.

N=10X10=100

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9x + 5 = 3

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3 years ago
Find the perimeter use 3.14
Alex777 [14]
Hey,
So we have to solve this in multiple steps. Step 1 is to find the circumference of the semi-circle and multiply by three since there are three. Step 2 would be to find the perimeter of the rectangle.  Step 3 would be to add those two together.

Step 1: To find the circumference of the semicircle use the formula pi (3.14) times radius (8 ÷ 2 = 4) times 2. After that we will divide by two since there is only half. After that we will multiply that answer by three.
C = 3.14 x 4 x 2
C = 12.56 x 2
C = 25.12

C = 25.12 ÷ 2
C = 12.56

Perimeter = 12.56 x 3 = 37.68

Step 2: To find the perimeter of the rectangle/square add all the sides (8).
Perimeter = 8 + 8 + 8 + 8 = 32

Step 3: Now add the two previous answers to get the final perimeter.
37.68 + 32 = 69.68

Final Answer: 69.68
Hope this helped!

Cheers,
Izzy

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