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3 years ago

Which best describes mitochondrial DNA (mtDNA)?

1 answer:

7 0

Mitochondrial is an organelle found in large numbers in most cells, in which the biochemical processes of respiration and energy production occur. It has a double membrane, the inner layer being folded inward to form layers (cristae).

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The average conversion energy from producers to primary consumers is a. 1% b. 10% C. 50% d. 100%

KATRIN_1 [288]

Answer:

The average conversion energy from producers to primary consumers is b. 10%.

Explanation:

This percentage actually holds true for all transfer of energy at any trophic level in the food chain. Majority of the energy loss can be attributed to metabolic processes that give off heat and other forms of energy. It is important to note that energy cannot be created nor destroyed, it is simply transformed from one form to another.

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3 years ago

Why is the alpine tundra biome worth protecting WELL GIVE BRAINLIEST IF YOU CAN HLO ME

IRISSAK [1]

Struggled with this earlier but because of the high altitude only some animals can live there and thrive because of the lower oxygen levels

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3 years ago

Which of the following characteristics would indicate why a virus is non-living?

lianna [129]

Answer:

Explanation:

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3 years ago

Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some

Sphinxa [80]

Answer and Explanation:

The number of observed individuals:

AA 42

AG 24

GG 21

Total number of individuals, N= 87 = 42 + 24 + 21

Allelic frequencies:

f(p) = (2 x AA + AG)/ 2 x N

f (p)= (2 x 42 + 24) /2 x 87

f (p) = (84 + 24) / 174

f (p)= 108 / 174

f (p) = 0.62

f (q) = (2 x GG + AG)/2 x N

f (q) = (2 x 21 + 24 )/2 x 87

f (q) = (42 + 24)/ 174

f (q) = 66/174

f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

The expected genotypic frequency:

F (AA)= 0.62 ² = 0.3844

F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712

F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

The number of expected individuals:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

Total number of expected individuals = 33.44 + 40.99 + 12.563 = 87

Chi square= sum (O-E)²/E

AA= (O-E)² /E

AA=(42 - 33.44) ² / 33.44

AA= 2.2

AB= (O-E)² /E

AB= (24 - 40.99)²/ 40.99

AB=7.04

BB=(O-E)² /E

BB= (21-12.563)²/12.563

BB= 5.66

Chi square= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

Degrees of freedom = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

5 0

3 years ago

Most of the energy needed by eukaryotic cells produced in

antiseptic1488 [7]

Answer: ATP

Explanation:Each organelle supports different activities in the cell. Mitochondria, for example, are organelles that provide eukaryotes with most of their energy by producing energy-rich molecules called ATP. Prokaryotes lack mitochondria and instead produce their ATP on their cell surface membrane.

hope i helped

4 0

3 years ago

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