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Darya [45]
4 years ago
9

A spinner of 10 divisions, numbered from 1 to 10, is spun and two coins are tossed. What is the probability to land on a prime n

umber in the spin and getting two tails from the two tosses?
Mathematics
1 answer:
pogonyaev4 years ago
6 0

Answer:

1/10

Step-by-step explanation:

There are 4 prime numbers from 1 to 10 (2,3,5,7). This makes the probability of getting a prime number as 4/10 = 2/5.

The probability of getting one tail is 1/2, making the proability of getting 2 to be (1/2)^2 = 1/4.

Multiply both probabilities together, and you get 2/5 * 1/4 = 1/10

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x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2

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6 0
3 years ago
How many different twotwo​-letter passwords can be formed from the letters
Anna [14]

Answer:

70

Step-by-step explanation:

GIVEN: two two​-letter passwords can be formed from the letters  A, B, C, D, E, F, G and H.

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SOLUTION:

Total number of different letters =8

for two two​-letter passwords 4 different are required.

Number of ways of selecting 4 different letters from 8 letters=^8C_4

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                                                                                                  =70

Hence there are 70 different two-letter passwords can be formed using 8 letters.

5 0
3 years ago
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