A spinner of 10 divisions, numbered from 1 to 10, is spun and two coins are tossed. What is the probability to land on a prime n
umber in the spin and getting two tails from the two tosses?
1 answer:
Answer:
1/10
Step-by-step explanation:
There are 4 prime numbers from 1 to 10 (2,3,5,7). This makes the probability of getting a prime number as 4/10 = 2/5.
The probability of getting one tail is 1/2, making the proability of getting 2 to be (1/2)^2 = 1/4.
Multiply both probabilities together, and you get 2/5 * 1/4 = 1/10
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