<span>Each shell is composed of one or more subshells. The first K shell has one subshell, called ‘1s’; the L shell has two subshells, called ‘2s’ and ‘2p’; the third shell has ‘3s’, ‘3p’, and ‘3d’; and so on. A subshell is the set of states defined by the azimuthal quantum number, l, within a shell. The values l = 0, 1, 2, 3 correspond s, p, d and f subshells, respectively. The maximum number of electrons which can occupy a subshell is given by 2(2l + 1). This gives two electrons in an s subshell, six electrons in a p subshell, ten electrons in a d subshell and fourteen electrons in an f subshell.</span>
Answer:
A strong acid completely ionizes in water.
Energy is not created or destroyed due to the law of Conservation of Energy. Hope this helps!
Answer:
yes it can
Explanation:
because, it depends on where the rock is, for example on a dessert it would Be cracked and things like that if near an eruption it would be the flamey black rock, and so on you get it
Answer : The rate of formation of 
is, 
Explanation : Given,
Rate of disappearance of 
= 
The given rate of reaction is,
The expression for rate of reaction :
![\text{Rate of disappearance}=-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[Cl_2]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%7D%3D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D%3D-%5Cfrac%7Bd%5BCl_2%5D%7D%7Bdt%7D)
![\text{Rate of formation}=\frac{1}{2}\frac{d[NOCl]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20formation%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNOCl%5D%7D%7Bdt%7D)
From this we conclude that,
![\frac{1}{2}\frac{d[NOCl]}{dt}=-\frac{d[Cl_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNOCl%5D%7D%7Bdt%7D%3D-%5Cfrac%7Bd%5BCl_2%5D%7D%7Bdt%7D)
![\frac{d[NOCl]}{dt}=2\times \frac{d[Cl_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNOCl%5D%7D%7Bdt%7D%3D2%5Ctimes%20%5Cfrac%7Bd%5BCl_2%5D%7D%7Bdt%7D)
Now put the value of rate of disappearance of , we get:
![\frac{d[NOCl]}{dt}=2\times (4.24\times 10^{-2}M/s)=8.48\times 10^{-2}M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNOCl%5D%7D%7Bdt%7D%3D2%5Ctimes%20%284.24%5Ctimes%2010%5E%7B-2%7DM%2Fs%29%3D8.48%5Ctimes%2010%5E%7B-2%7DM%2Fs)
Therefore, the rate of formation of is,
