A variable that stays the same
The moles of I2 that will form 38.58g of Ni3 is 0.147 moles
calculation
write the equation for reaction for formation of Ni3 from I2 and N2
that is 3I2 + N2 = 2NI3
find the moles of Ni3 formed = mass/molar mass
= 38.58g/ 394.71 g/mol = 0.098 moles
by use of mole ratio between I2 to NI3 which is 3 :2 the moles of I2
= 0.098 x3/2 = 0.147 moles
This is an exercise in<u> the General Combined Gas Law</u>.
To start solving this exercise, we obtain the following data:
<h3>
Data:</h3>
- V₁ = 4.00 l
- P₁ = 365 mmHg
- T₁ = 20 °C + 273 = 293 K
- V₂ = 2,80 l
- T₂ = 30 °C + 273 = 303 K
- P₂ = ¿?
We apply the following formula:
- P₁V₁T₂=P₂V₂T₁ ⇒ General formula
Where:
- P₁=Initial pressure
- V₁=Initial volume
- T₂=end temperature
- P₂=end pressure
- T₂=end temperature
- V₁=Initial temperature
We clear for final pressure (P2)

We substitute our data into the formula:



Answer: The new canister pressure is 539.224 mmHg.
<h2>{ Pisces04 }</h2>
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